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solniwko [45]
3 years ago
8

Match each item with a statement below.â

Computers and Technology
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

a. Anycast Addresses

b. Broadcast domain

c. Classless Interdomain Routing (CIDR)

d. Extended Unique Identifier (EUI-64) interface ID

e. Intra-Site Automatic Tunnel Addressing Protocol (ISATAP)

f. IP prefix

g. Loopback Address

h. Metric

i. Multicasting

j. Teredo

Explanation:

a. <u>Anycast Addresses</u>: An address type used in IPv6 to allow a one-to-many relationship between source and destination.

b. <u>Broadcast domain</u>: The bounds of a network that defines which devices must receive a packet that's broadcast by any other device.

c. <u>Classless Interdomain Routing (CIDR)</u>: A method of IP addressing in which the network and host IDs are determined by a prefix number that specifies how many bits of the IP address are network bits.

d. <u>Extended Unique Identifier (EUI-64) interface ID</u>: An auto configure IPv6 host address that uses the MAC address of the host plus an additional 16 bits.

e. <u>Intra-Site Automatic Tunnel Addressing Protocol (ISATAP)</u>: An automatic tunneling protocol used to transmit IPv6 packets between dual IP layer hosts across an IPv4 network.

f. <u>IP prefix</u>: A value used to express how many bits of an IP address are network ID bits.

g. <u>Loopback Address</u>: An address that always refers to the local computer. The loop address is primarily 127.0.01.

h. <u>Metric</u>: A value assigned to the gateway based on the speed of the interface used to access the gateway.

i. <u>Multicasting</u>: A network communication in which a packet is addressed so that more than one destination can receive it

j. <u>Teredo</u>: An automatic IPv6-over-IPv4 tunneling protocol that solves the problem of 6to4's requirement of a public IPv4 address and the inability to traverse NAT routers.

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Answer:

negatives = []

zeros = []

positives = []

while True:

   number = input("Enter a number: ")

   if number == "":

       break

   else:

       number = int(number)

       if number < 0:

           negatives.append(number)

       elif number == 0:

           zeros.append(number)

       else:

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for n in negatives:

   print(n)

for z in zeros:

   print(z)

for p in positives:

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Explanation:

Initialize three lists to hold the numbers

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Inside the loop:

If the number is smaller than 0, put it in the negatives list

If the number is 0, put it in the zeros list

Otherwise, put the number in the negatives list

When the while loop is done, create three for loops to print the numbers inside the lists

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Answer:

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