Answer:
The answer to your question is 308.1 g of KmNO₄
Explanation:
Data
Volume = 6 L
Concentration = 0.325 M
Molar mass of Potassium permanganate = 39 + 55 + (16 x 4) = 158 g
Process
1.- Calculate the moles of KMnO₄
Formula
Molarity = moles/volume
moles = molarity x volume
moles = 0.325 x 6
moles = 1.95
2.- Calculate the grams of KMnO₄
158 g KMnO₄ ------------------ 1 mol
x ------------------ 1.95
x = (1.95 x 158)/1
x = 308.1 g
Answer:
<em>The first three options given out of the five options are correct.</em>
- <em>It collects chemical data.
</em>
- <em>It records real-time sampling data.
</em>
- <em>It processes and stores chemical data.</em>
Explanation:
An electronic air sampler is a device that is used by people to check apprehension of contamination having individuals with the help of certain volume of air sampling.
The Device is used for recording the chemical data of contamination and the real-time data is sampled and recorded and the data is processed and stored. The air sampling is done in two ways.
Its C..... A pegmatitic is a crystals usually larger than 2.5 cm in size.... look in to it? :)
Answer: A. It indicates the direction in which the reaction occurs.
Answer: -
24.24 mL
Explanation: -
Mass of CaCO₃ = 1.212 g
Molar mass of CaCO₃ = 40 x 1 +12 x 1 + 16 x 3 = 100 g / mol
Number of moles of CaCO₃ =
= 0.01212 mol
The balanced chemical equation for the reaction that occurs when CaCO₃ is added to HCl is
CaCO₃ + 2HCl --> CaCl₂ + H₂O + CO₂
From the equation we see
1 mol of CaCO₃ reacts with 2 mol of HCl
0.01212 mol of CaCO₃ react with
= 0.02424 mol of HCl
Strength of HCl = 1 M
Volume of HCl required = Number of moles of HCl / strength of HCl
= 0.02424 mol / 1 M
= 0.02424 L
= 0.02424 x 1000 mL
= 24.24 mL