A. R groups interact to form disulfide bonds or ionic bonds. - <span>tertiary and quaternary
</span><span>
B. Several polypeptide chains in a \beta-pleated sheet are held together by hydrogen bonds between adjacent chains. s</span><span>econdary, tertiary, or quaternary
</span><span>
C. Hydrogen bonding between amino acids in the same polypeptide gives a coiled shape to the protein. </span><span>primary</span>
Answer:
1.69 g Na₂O
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
0.0273 mol Na₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of Na - 22.99 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol
<u>Step 3: Convert</u>
<u />
= 1.69205 g Na₂O
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
1.69205 g Na₂O ≈ 1.69 g Na₂O
Answer:
Mercury
Explanation:
This is the only metal that exists as a liquid at room temperature
N2 has the optimal bond order of 3. To form N2+, one bonding electron is removed, giving a bond order of 2.5. Similarly, to form N2-, one antibonding electron is added, also giving a bond order of 2.5.
Answer:
b. The nitrogen atom shares one valence electron with each iodine atom, which also shares one valence electron each with the nitrogen atom.
Explanation:
The formula of nitrogen triiodide is NI3. In this compound, the nitrogen atom shares one valence electron with each chlorine atom which in turn also shares a valence electron with nitrogen.
Recall that covalent bonding involves a sharing of <u>valence </u> electrons. Transfer of electrons is typical of ionic bonds between a metal and a nonmetal. nitrogen and iodine are nonmetals hence they bond covalently.
Hence, the formation of NI3 leaves three lone pairs on each chlorine atom and one lone pair on the nitrogen atom.