Answer:
0.486 L
Explanation:
Step 1: Write the balanced reaction
2 KCIO₃(s) ⇒ 2 KCI (s) + 3 O₂(g)
Step 2: Calculate the moles corresponding to 1.52 g of KCIO₃
The molar mass of KCIO₃ is 122.55 g/mol.
1.52 g × 1 mol/122.55 g = 0.0124 mol
Step 3: Calculate the moles of O₂ produced from 0.0124 moles of KCIO₃
The molar ratio of KCIO₃ to O₂ is 2:3. The moles of O₂ produced are 3/2 × 0.0124 mol = 0.0186 mol
Step 4: Calculate the volume corresponding to 0.0186 moles of O₂
0.0186 moles of O₂ are at 37 °C (310 K) and 0.974 atm. We can calculate the volume of oxygen using the ideal gas equation.
P × V = n × R × T
V = n × R × T/P
V = 0.0186 mol × (0.0821 atm.L/mol.K) × 310 K/0.974 atm = 0.486 L
I am 90 percent positive that the answer is the first option "Its results are inconsistent over experiments"
The major product obtained when 1-hexyne is treated with H2 and Pd is; 1-hexene.
The structure of 1-hexyne is such that it possesses a triple bond around its first Carbon in it's carbon chain.
On this note; hydrogenation by treatment with H2 and Paladium, Pd as catalyst yields 1-hexene as the major product.
PS: Paladium, Pd is the major constituent of the Lindlar's catalyst.
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86198Rn => 24He + 84194Po
The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.
