Answer:
0.20 moles
Explanation:
The pressure is proportional to the quantity of gas at a given temperature and volume. So, the quantity needs to be increased by a factor of ...
(35 psi)/(29.2 psi) = 175/146 ≈ 1.19863
The fractional increase required is ...
1.19863 -1 = 0.19863
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The quantity of air currently in the tire is ...
1 mol·519.67°R/(atm·23.6442 L) × (29.2/14.7 atm) × (11.6 L) / (45+459.67)°R
= 1.0035 mol
so we need to add ...
(fraction to add) × (current quantity) = amount to add
0.19863 × 1.0035 mol = 0.1993 mol = amount to add
About 0.20 moles of air must be added to the tire to bring the pressure up.
Molarity is the number of moles of solute in 1 L of solution.
the mass of NaCl added - 20.45 g
number of moles of NaCl - 20.45 g / 58.5 g/mol = 0.350 mol
volume of the solution is 700.0 mL
since molarity is the number of moles in 1000 mL
and if 700.0 mL contains - 0.350 mol
therefore 1000 mL contains - 0.350 mol / 700.0 x 1000 = 0.500 mol
hence molarity of solution is 0.500 M
Answer:
In an equilibrium mixture of the three gases, PCO = PCl2 = 2.22 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is kp=(COCl2)/(CO)(Cl2) which is . So, the correct answer is 7.34.
