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Irina-Kira [14]
3 years ago
5

What mass of lithium phosphate would you mass to make 2.5 liter of 1.06 M lithium

Chemistry
1 answer:
alex41 [277]3 years ago
5 0

Answer:

Approximately 3.06 \times 10^{2}\; \rm g (approximately 306\; \rm g.)

Explanation:

Calculate the quantity n of lithium phosphate in V = 2.5\; \rm L of thisc = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1} lithium phosphate solution.

\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}.

Empirical formula of lithium phosphate: \rm Li_3PO_4.

Look up the relative atomic mass of \rm Li, \rm P,and \rm O on a modern periodic table:

  • \rm Li: 6.94.
  • \rm P: 30.974.
  • \rm O: 15.999.

Calculate the formula mass of \rm Li_3PO_4:

M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}.

Calculate the mass of that n = 2.65\; \rm mol of \rm Li_3PO_4 formula units:

\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}.

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