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son4ous [18]
4 years ago
15

How can I find the Slope intercept

Mathematics
2 answers:
allsm [11]4 years ago
8 0
Y=m(x)+B is the slope intercept formula 
JulijaS [17]4 years ago
3 0
Y =max+b that’s the equation
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Find the greatest common factor of the terms: 35a⁴b⁸, 49a²b⁵, 14ab⁴?​
AleksandrR [38]

Answer:

7ab^4

Step-by-step explanation:

all of the coefficients have 7 as a GCF. for a and b you can only pull out as much as the lowest term.

that should be correct and hope this helps!

4 0
3 years ago
Find m1<br>please helpp​
Katyanochek1 [597]

Answer:88 degrees

Step-by-step explanation:

6 0
4 years ago
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Examine this system of equations. What integer should the second equation be multiplied by so that when the two equations are ad
Zepler [3.9K]

Answer:

Step-by-step explanation:

we should multiply the 1/8 on the 2nd equation, by some number "n", such that our result will be equals to -3/4, namely the above x-coefficient but negative, or different sign, so (rest of the explanation is in the picture attached)

3 0
3 years ago
Among all pairs of numbers (x,y)such that 6x+2y=36 find the pair for which the sum of squares, x^2+y^2 is minimum.
lora16 [44]
First, we simplify 6x+2y=36 into 3x+y=18 by dividing by 2. This means that y=-3x+18.


The sum x^2+y^2 can be written as: x^2+y^2=(x+y)^2-2xy, 
<span>
from the binomial expansion formula: </span>(x+y)^2=x^2+2xy+y^2.
<span>
Thus, substituting </span>y=-3x+18 and simplifying we have<span>

</span>x^2+y^2=(x+(-3x+18))^2-2x(-3x+18)=(-2x+18)^2+6x^2-36x=4x^2-72x+18^2+6x^2-36x=10x^2-108x+18^2.

This is a parabola which opens upwards (the coefficient of x^2 is positive), so its minimum is at the vertex. To find x, we apply the formula -b/2a. Substituting b=-108, a=10, we find that x is 108/20=5.4.


At x=5.4, the expression 10x^2-108x+18^2, which is equivalent to x^2+y^2, takes it smallest value.

Substituting, we would find 10x^2-108x+18^2=10(5.4)^2-108(5.4)+18^2=291.6-583.2+324=32.4 This is the smallest value of the expression. 


For x=5.4, y=-3x+18=-3(5.4)+18=1.8.



Answer:   (5.4, 1.8)
8 0
3 years ago
(05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(5, 2). What is the length of
Cerrena [4.2K]

Answer:  11 units

Step-by-step explanation:

Given: On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(5, 2).

To find : length of Side RT of the polygon.

Using distance formula  to find distance between (a,b) and (c,d):

d=\sqrt{(d-b)^2+(c-a)^2}

Length of RT = \sqrt{(2-2)^2+(5-(-6))^2}

\\\\=\sqrt{0+(5+6)^2}\\\\= \sqrt{11^2}\\\\=11

hence, the length of RT = 11 units.

6 0
4 years ago
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