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3 years ago

I need help ASAP

Mathematics

1 answer:

kirill115 [55]3 years ago

5 0

Answer is 40,000+3,500n = 51,000 +2,800n I think u didn’t put the n in A so A?

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

The function f(x) = x^2 is an even function.

Vika [28.1K]

Answer:

..................

Step-by-step explanation:

................................

6 0

2 years ago

Solve the inequality. 2(4+2x)25x+5

stealth61 [152]

Answer:

Step-x ≤ 3

Given

2(4 + 2x) ≥ 5x + 5 ← distribute parenthesis on left side

8 + 4x ≥ 5x + 5 ( subtract 4x from both sides )

8 ≥ x + 5 ( subtract 5 from both sides )

3 ≥ x , hence

x ≤ 3by-step explanation:

3 0

3 years ago

You purchased a vehicle for $11,578 with a down payment of $4,100. You had 36 monthly payments of $251.34. Calculate the finance

Leona [35]

Finance charge is a fee that represents the cost of borrowing or credit.
In this equation, it shows the total amount paid through credit subtracted by the cost of vehicle.
let x be the finance charge

x = $4,100 + 36 months ($251.34/month) - $11,578
x = $4,100 + $9,048.24 - $11,578 
x = ($4,100 + $9,048.24) - $11,578
x = $13,148.24 - $11,578
x = $1,570.24.
The finance charge is $1,570.24

6 0

3 years ago

Hey guys i need some heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp- 15 points

masya89 [10]

Answer:

Step-by-step explanation:

3x + 2 + 58 = 90

3x + 60 = 90

3x = 30

x = 10

it's adjacent

8 0

3 years ago