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4 years ago

Evaluate this expression. y + 7, if y = 12

Mathematics

2 answers:

photoshop1234 [79]4 years ago

6 0

Answer:

$\huge{ \boxed{ \sf{19}}}$

Step-by-step explanation:

$\underline{ \sf{Given}} : \sf{y = 12}$

$\underline{ \sf{To \: Find}} : \sf{Value \: of \: the \: given \: expression}$

$\sf{y + 7}$

plug the value of y

$\mapsto{ \sf{12 + 7}}$

Add the numbers: 12 and 7

$\mapsto{ \sf{19}}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

NemiM [27]4 years ago

3 0

Y=5
Reasoning is because 7+5=12

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We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

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