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cluponka [151]
3 years ago
12

Freddy is buying wings and nachos for a party. a box of ten wings cost $7.00 Nachos cost $4.00 per tray. He must spend less than

$40 on the wings and nachos. Using x to represent each box of wings and y to represent each tray of wings and y to represent each tray of nachos. Create an inequality that correctly represents the possible number of boxes of wings and trays of nachos that freddy can buy and still be within his budget.
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0
Hey there! The answer is 7x + 4y < 40

Let's first rearrange our data in a more structured way.

x represents a box of wings which has a cost of $7.00. Therefore the total cost of the boxes is 7x.

y represents a tray of nachos which has a cost of $4.00. Therefore the total cost of the trays is 4y.

The sum of the costs of trays and boxes, which is (7x + 4y) must be smaller than $40.

Now we can set up the inequality.
7x + 4y < 40

~ Hope this helps you!
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Answer:

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Step-by-step explanation:

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Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at
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a) The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively.

b) The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

P'(x,y) = k\cdot P(x,y) (1)

Where:

  • P(x,y) - Original point
  • P'(x,y) - Dilated point.

If we know that k = \frac{1}{3}, A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3), then the new points of the quadrilateral are:

A'(x,y) = \frac{1}{3}\cdot (0,6)

A'(x,y) = (0, 2)

B'(x,y) = \frac{1}{3} \cdot (-3,-6)

B'(x,y) = (-1, -2)

C'(x,y) = \frac{1}{3}\cdot (-9,-6)

C'(x,y) = \left(-3,-2\right)

D'(x,y) = \frac{1}{3}\cdot (-12,-3)

D'(x,y) = (-4, -1)

The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively. \blacksquare

b) A translation along a vector is defined by following operation:

P'(x,y) = P(x,y) +T(x,y) (2)

Where T(x,y) is the transformation vector.

If we know that T(x,y) = (-5,-1), A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3),

A'(x,y) = (0,6) + (-5, -1)

A'(x,y) = (-5, 5)

B'(x,y) = (-3, -6) + (-5, -1)

B'(x,y) = (-8,-7)

C'(x,y) = (-9, -6) + (-5, -1)

C'(x,y) = (-13, -7)

D'(x,y) = (-12,-3)+(-5,-1)

D'(x,y) = (-17, -4)

The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively. \blacksquare

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

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