Answer:
A) E° = 4.40 V
B) ΔG° = -8.49 × 10⁵ J
Explanation:
Let's consider the following redox reaction.
2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)
We can write the corresponding half-reactions.
Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq) E°red = 1.36 V
Anode (oxidation): 2 Li(s) → 2 Li⁺(aq) + 2 e⁻ E°red = -3.04
<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>
The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.
E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V
<em>B) Calculate the free energy ΔG° of the reaction.</em>
We can calculate Gibbs free energy (ΔG°) using the following expression.
ΔG° = -n.F.E°
where,
n are the moles of electrons transferred
F is Faraday's constant
ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J
The answer is certain chemical symbols on the periodic table were named not anlyafter the people who discovered them. some of their chemical symbols were even taken from their Latin names. in sodium's case it was taken from it's original Latin name, natrium, as is na.
Answer:
The periodic table is a tabular display of the chemical elements organized on the basis of their atomic numbers, electron configurations, and chemical properties. ... Elements with the same number of valence electrons are kept together in groups, such as the halogens and the noble gases.
Causes carbon to move from one reservoir to another
As given that some volume of water has been dispensed say "x mL"
The initial weight of bottle =8.4376 g
The final weight of bottle + water =28.5845 g
So weight of water transferred = 28.5845 g - 8.4376 g = 20.1469 g
Now there is a relation between density, mass and volume
density = mass / volume
Therefore
Volume = mass / density
So volume of water dispensed = mass dispensed / density =20.1469 g / 0.9967867 g/ml.
Volume of water = 20.2118467 mL