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AleksAgata [21]
4 years ago
8

How do you convert scientific notation into SI base units?

Chemistry
1 answer:
Jobisdone [24]4 years ago
6 0
For example 4.698*10^4
This is scientific notation
=46980
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Balance electrons are found:
baherus [9]

Answer:

The answer is C

Explanation:

Now rate me and thank me

6 0
3 years ago
Read 2 more answers
The following reactions are used in batteries:Reaction I is used in fuel cells, II in the automobile lead-acid battery, and III
elixir [45]

The highest ratio is -0.613kj/g which is for automobile lead-acid battery .

Given ,

Reaction-1 used in fuel cells

Reaction-2 used in automobile lead-acid battery

Reacttion-3 used in experimental high-temperature battery for powering electric vehicles .

1) Fuel cells :

2H2(g) + O2(g) ==> 2H20 (l)   ,    E^0cell = 1.23V

We know ,

Free energy is the maximum work done .

delta G = Wmax

=> Wmax = delta G = -4.75*10^5j/mol e^- = -4.75*10^2 kj/ mol e^-

Molecular mass of 1 mole of H2  = 2 .016 g / mol e^-

Molecular mass of 2 mole of H2 = 4.032 g/mol e^-

Molecular mass of O2 = 32 g/mol e^-

Total mass of the reactants = (4.032+32)g/mol e^- = 36.032 g/mol e^-

Ratio of Wmax to the total mass of the reactants

=Wmax/ total mass of the reactants

=( -4.75*10^2 kj/mol e^-)/36.032 g/mol e^-

=-13.2kj/g

Therefore , the ratio of Wmax to total mass of the reactants is -13.2kj/g .

2) Automobile lead-acid battery :

Pb(s) + PbO2(s) + 2H2SO4(aq) ==> 2PbSO4 (s) + 2H2O (l)  ,  E^0cell = 2.04V

We know ,

Wmax = delta G = -3.94*10^5j/mol e^- = -3.94*10^2kj/mol e^-

molecular mass of Pb = 207.2 g /mol e^-

molecular mass of Pbo2 = 239.2g/mol e^-

molecular mass of H2SO4 = 98.008g/mol e^-

molecular mass of 2 mole of H2SO4 = 196.016g/mol e^-

total mass of the reactants = (207.2+239.2+196.016)g/mol e^- = 642.416g/mol e^-

Ratio of Wmax to total mass of the reactants

= Wmax/total mass of reactants

=(-3.94*10^2kj/mol e^-)/642.416g/mol e^-

=-0.613kj/g

Hence ,the ratio of Wmax to the total mass of the reactants of automobile lead-acid battery is -0.613kj/g .

3) Experimental high temperature battery :

2Na(l) +FeCl2(s) ==> 2NaCl (s) + Fe(s)     ,     E^0 cell = 2.35V

We know ,

Wmax = delta G = -4.53*10^5j/mol e^- = -4.53*10^2kj/mol e^-

molecular mass of Na = 22.99 g/mol e^-

molecular mass of 2 moles of Na = 45.98g/mol e^-

molecular mass of FeCl2 = 126.85 g/mol e^-

total mass of the reactants =( 45.98+ 126.85)g/mol e^- = 172.83 g/mol e^-

Ratio of Wmax to the total mass of the reactants

= Wmax / total mass of reactants

=(-4.53*10^2kj/mol e^-)/ 172.83g/mol e^-

=-2.62kj/g

Therefore , the ratio of Wmax to the total mass of the reactants in an experimental high temperature battery is -2.62kj/g .

Hence , the highest ratio is -0.613kj/g which is of lead -acid battery .

Learn more about fuel cell here :

brainly.com/question/13603874

#SPJ4

4 0
2 years ago
Which statement is true? Postively charged objects attract other positively charged objects negatively charged objects attract o
ANEK [815]

Answer:

Explanation:one is true because if it is positiveit would not be attracting it would be sepperating

8 0
3 years ago
A person suspects that an unknown liquid is water. he adds 110.0 J of heat to 55.0 g of liquid. The temperature of the liquid in
Tema [17]

Explanation:

First thing first, you mistyped the specific heat of water, which should be

c

water

=

4.18

J

g

∘

C

Now, a substance's specific heat tells you how much heat is required to increase the temperature of

1 g

of that substance by

1

∘

C

.

In the case of water, you would need

4.18 J

to increase the temperature of

1 g

of water by

1

∘

C

.

Notice that your sample of water has a mass of

1 g

as well, which means that the only factor that will determine the amount of heat needed will be the difference in temperature.

The equation that establishes a relationshop between heat and change in temperature looks like this

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed

c

- the specific heat of the substance, in your case of water

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature

Plug in your values and solve for

q

to get

q

=

1.00

g

⋅

4.18

J

g

⋅

∘

C

⋅

(

83.7

−

26.5

)

∘

C

q

=

239.096 J

Rounded to three sig figs, the answer will be

q

=

239 J

5 0
3 years ago
Calculate the number of moles in 8 g of water.
polet [3.4K]

Answer:

refer the above attachment

4 0
2 years ago
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