Answer:
Volume of sample after droping into the ocean=0.0234L
Explanation:
As given in the question that gas is idealso we can use ideal gas equation to solve this;
Assuming that temperature is constant;
Lets
and
are the initial gas parameter before dropping into the ocean
and
and
are the final gas parameter after dropping into the ocean
according to boyle 's law pressure is inversly proportional to the volume at constant temperature.
hence,

P1=1 atm
V1=1.87L
P2=80atm
V2=?
After putting all values we get;
V2=0.0234L
Volume of sample after droping into the ocean=0.0234L
Once the water evaporates, you will start to see the minerals that were present in the water before it changed state. If the water was from the ocean, you will see salt crystals in the evaporated water. If the water was fresh, you may see other minerals typically found in fresh water.
Answer:
- <u>Freezing point: - 1.83ºC</u>
- <u>Boiling point: 100.50ºC</u>
Explanation:
The <em>freezing point</em> and<em> boiling point</em> of solvents, when a solute is added, will change accordingly to the concentration of the solute particles.
The freezing point will decrease and the boiling point will increase. These are two colligative properties.
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Explanation:
This is correct!
Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.
An example is;
Na+(aq) + Cl−(aq) + Ag+(aq) + NO3−(aq) → Na+(aq) + NO3−(aq) + AgCl(s)
The ions; Na+, NO3−(aq) would be cancelled out to give;
Cl−(aq) + Ag+(aq) → AgCl(s)