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Crazy boy [7]
2 years ago
5

Two different types of tea are sold in your store. If you know 100 cups of tea were sold and one type sold 5 times as much as th

e other type, how much of each type of tea were sold?
Mathematics
1 answer:
LiRa [457]2 years ago
8 0

The answer can not be found from the given information

Step-by-step explanation:

Two different types of tea are sold in your store

  • You know 100 cups of tea were sold
  • One type sold 5 times as much as the other type

We need to find how much of each type of tea were sold

Assume that the two types are x and y

∵ x represents one type of tea

∵ y represents the other type of tea

∵ 100 cups of tea where sold

- Add x and y, then equate the sum by 100

∴ x + y = 100 ⇒ (1)

∵ x type is 5 times as much as y type

∴ x = 5y ⇒ (2)

Now we have a system of equations to solve it

Substitute x in equation (1) by equation (2)

∴ 5y + y = 100

∴ 6y = 100

- Divide both sides by 6

∴ y = 16.67

<em>But you know number cups must be whole numbers</em>

The number cups can be 102 <em>OR</em> one type is 4 times as much as the other type

If the number of cups is 102, then

85 cups of one type and 17 cups of the other type were sold

If one type is 4 times as much as the other type, then

80 cups of one type and 20 cups of the other type were sold

The answer can not be found from the given information

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

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2 years ago
In a batch of 280 water purifiers, 12 were found to be defective. What is the probability that a water purifier chosen at random
aleksley [76]
This is experimental probability.

If 12 were found to be defective out of 280 the experimental probability of a purifier being defective is:

12/280 which is:

4.3%  (to nearest tenth of a percent)
6 0
3 years ago
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aleksandr82 [10.1K]
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2 years ago
a. Determine all bijections from the {1,2,3} into {a,b,c}. b. Determine all bijections from {1, 2, 3} into {a,b,c,d}.
avanturin [10]

Part A

There are 6 bijections from {1,2,3} to {a,b,c}. This is effectively the same as asking the question "how many ways are there to arrange {a,b,c} where order matters?" We use a factorial to answer this question.

3 factorial = 3! = 3*2*1 = 6

You can also use a permutation, which is composed of factorials, to get the same answer.

======================================================

Part B

There are no bijections from {1,2,3} to {a,b,c,d}. Why is this? Because a bijection has two properties: it must be one-to-one, and it must be onto. The term "onto" in mathematics means "every value in the range is targeted". In the case of the range {a,b,c,d} it is not possible for each value to show up. This is because there are only three items in the domain {1,2,3}. You'll always be one letter short.

As you can probably guess, a bijection is only possible if and only if n(D) = n(R), where D and R are the domain and range respectively. The notation n(D) represents the count or number of items in set D.

3 0
3 years ago
An angle measure of 55.45 is converted to DMS notation as
jek_recluse [69]

Converting angle measure of 55.45 to DMS notation we get 55 degrees 27 minutes 0 seconds

Step-by-step explanation:

We need to convert angle measure of 55.45 to DMS notation

DMS notation is Degree Minute and seconds

Solving:

We have 55.45, the value before decimal is considered as degrees and values after decimal can be minutes and seconds.

We can write it as 55 and 0.45

So, we have 55 degrees

To find minutes we will multiply 0.45 by 60

0.45*60 = 27 minutes

Since we have no decimal value in minutes so seconds will be 0

So, DMS will be 55 degrees 27 minutes 0 seconds

Hence converting angle measure of 55.45 to DMS notation we get 55 degrees 27 minutes 0 seconds

5 0
3 years ago
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