Answer:
E. II, III
Explanation:
Let's consider the following reaction.
C₂H₅OH(l) + 3 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(l)
ΔH = -1.37 × 10³ kJ
<em>Consider the following propositions:</em>
<em>I. The reaction is endothermic.</em> FALSE. By convention, if the enthalpy of the reaction ΔH is negative, the reaction is exothermic.
<em>II. The reaction is exothermic.</em> TRUE.
<em>III. The enthalpy term would be different if the water formed was gaseous. </em>TRUE. The enthalpy of the reaction depends on the enthalpies of formation (ΔHf) of reactants and products. ΔHf of H₂O(l) is different from ΔHf of H₂O(g).