The amount of heat lost by the copper is 2402.4 J.
To Calculate the amount of heat lost, we use the formula below.
<h3>Formula:</h3>
- Q = cm(t₂-t₁)................. Equation 1
<h3>Where:</h3>
- Q = Amount of heat lost
- c = specific heat capacity of copper
- m = mass of copper
- t₂ = Final temperature
- t₁ = Initial temperature
From the question,
<h3>Given:</h3>
- m = 78 g
- c = 0.385 J/g°C
- t₂ = 120°C
- t₁ = 40°C
Substitute these values into equation 1.
- Q = 78(0.385)(120-40)
- Q = 2402.4 J
Hence, The heat lost by the copper is 2402.4 J
Learn more about heat here: brainly.com/question/13439286
Answer:
6CO2 + 6H20 ----> C6H12O6 + 6O2
Explanation:
(Carbon Dioxide) + (Water) ------> (Glucose) + (Oxygen)
From the equation of the reaction; for every 1 mole of copper, the reaction uses 2 moles of silver nitrate.
<h3>What is a reaction?</h3>
A chemical reaction involves the transformation of one chemical specie into another. The reaction is not shown here hence the question is incomplete.
However, the reaction should be of the sort; Cu + 2AgNO3 ---> Cu(NO3)2 + Cu. Thus, for every 1 mole of copper, the reaction uses 2 moles of silver nitrate.
Learn more about chemical reaction: brainly.com/question/6876669
One of the examples of Boyles law in action is a syringe
What is your question please write properly>-< >_