Answer:
The answer would be meniscus.
Answer:
1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰
Explanation:
Cd is the last element in the 4d block of the Periodic Table (see Figure).
It has the electron configuration of Kr, plus filled 5s and 4d subshells.
Thus, its electron configuration is
1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰
Answer:
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ċօʀʀɛċt ʍɛ ɨʄ ɨʍ աʀօռɢ (-_^)
Answer:
a) X belongs to Group 1A
b) X belongs to Group 7A
c) x belongs to Group 3A
Explanation:
It is important to know the oxidation number of the elements in order to understand how the answers were obtained.
The oxidation number is obatined from their valency (or put it simply, group number).
Also, the oxidation number of a molecule is Zero.
In the first option,
O has an ox. number of -2, P has an ox. number of +5, and the molecule has an ox number of 0.
In the form of an equation we have,
3(x) + 5 + 4(-2) = 0
3x + 5 - 8 = 0
3x - 3 = 0
x = 3/3
x = 1 (Group 1).
In the second option,
Ca has an ox. number of +2, and the molecule has an ox. number of 0.
In the form of an equation we have,
2 + 2(x) = 0
2x = -2
x = -2/2
x = -1
This means it needs one mre electron to complete its octet. a characteristic of the group 7 elements.
In the third option,
S has an ox. number of +6, O has an ox. number of +2 and the molecule has an ox. number of 0.
In the form of an equation we have,
2(x) + 3[6 + 4(-2)] = 0
2x + 3(-2) = 0
2x = 6
x = 6/2 = 3 (Group 3)
