100+7.8=107.8 degrees. Which is now your new boiling point.
Answer:
Explanation:
Let A₀ = the original amount of ⁵⁵Co
.
The amount remaining after one half-life is ½A₀.
After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.
After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀.
The general formula for the amount remaining is:
A =A₀(½)ⁿ
where n is the number of half-lives
n = t/t_½
Data:
A = 1.90 ng
t = 45 h
t_½ = 18.0 h
Calculation:
(a) Calculate n
n = 45/18.0 = 2.5
(b) Calculate A
1.90 = A₀ × (½)^2.5
1.90 = A₀ × 0.178
A₀ = 1.90/0.178 = 10.7 ng
The original mass of ⁵⁵Co was .
It’s a heterogeneous mixture.
Answer:
C. C₆H₁₂
Explanation:
Alkenes are the unsaturated hydrocarbons which form a homologous series with a general formula;
Cₙ H₂ₙ
n in this problem is 6
2n = 2 x 6 = 12
The formula of the compound will be C₆H₁₂
Answer:
Number of mole = 0.0342 mole of Boron
Explanation:
One mole of a substance is equal to 6.022 * 10^23 units of that substance.
According to the definition in chemistry, mole is defined as the mass of substance containing the same number of fundamental units.
To calculate the number of mole, we will use the formula
n = m/Mm
n = number of mole
m = number of mass
Mm = number of molar mass
Molar mass of boron = 10.811g/mol
Mass of boron = 3.70 * 10^-1g
Using the formula
n = m/Mm
n = 3.70 * 10^-1 / 10.811g/mol
n = 0.0342 mole
