A plant makes its own food from the water and sun
28 gram of c2h4 must burn as it is equavilant to 1 mole of c2h4
Answer:
54.2 g of Ca(OH)₂
Explanation:
Let's determine the moles of solute, we should need
Molarity . volume (L) = moles
Let's convert 600 mL to L
600 mL/ 1000 = 0.6L
1.22 mol/L . 0.6L = 0.732 moles
Finally we must convert the moles to mass ( moles . molar mass)
0.732 mol . 74.08 g/mol = 54.2 g
The third class lever s<span>have </span>the effort<span> placed amongst </span>load<span> and the fulcrum.</span>
The balanced reaction equation for the combustion of butane is as follows;
C₄H₁₀ + 13/2O₂ ---> 4CO₂ + 5H₂O
the limiting reactant in this reaction is C₄H₁₀ This means that all the butane moles are consumed and amount of product formed depends on the amount of C₄H₁₀ used up.
stoichiometry of C₄H₁₀ to H₂O is 1:5
mass of butane used - 6.97 g
number of moles - 6.97 g / 58 g/mol = 0.12 mol
then the number of water moles produced - 0.12 mol x 5 = 0.6 mol
Therefore mass of water produced - 0.6 mol x 18 g/mol = 10.8 g