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3 years ago

Identify 3 distractions for young drivers and explain how you plan to minimize these distractions

Engineering

2 answers:

Ghella [55]3 years ago

6 0

Answer: devices,overthinking or rush and lack of experience

Explanation: devices: most young drivers tend to be on their devices 50% of time while driving and this could lead to lack of concentration hereby causing an accident.

overthinking or rush: on days where we are late to school ,appointments e.t.c we tend to rush and we end up forgetting some things same with driving when they rush they tend to lose concentration and focus and this eventually needs to overthinking

lack of experience: this is mainly common with people who drive without permission or a driver's license so they eventually have an accident when they do not have experience due to panic and other things.

Veseljchak [2.6K]3 years ago

4 0

Answer:

Phone, Eating, People in the car

Explanation:

your phone should always be off while driving and put away. Eating much like texting takes your attention away from the road so you should wait till you're parked or home to eat. People thrashing around or talking very loudly can be a terrible distraction. Ask them nicely to quiet down so you can focus on the road.

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Solid rockets can experience significant 2 phase flow. a) True b) False

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Answer:

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3 years ago

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Explanation:

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3 years ago

write a paragraph on how iron and copper(separately) is manufactured, what it consists of and processes that it went through to

trasher [3.6K]

Answer:

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3 years ago

A controller on an electronic arcade game consists of a variable resistor connected across the plates of a 0.227 μF capacitor. T

anyanavicka [17]

Answer:

R min = 28.173 ohm

R max = 1.55 × $10^{4}$ ohm

Explanation:

given data

capacitor = 0.227 μF

charged to 5.03 V

potential difference across the plates = 0.833 V

handled effectively = 11.5 μs to 6.33 ms

solution

we know that resistance range of the resistor is express as

V(t) = $V_o \times e^{t\RC}$ ...........1

so R will be

R = $\frac{t}{C\times ln(\frac{V_o}{V})}$ ....................2

put here value

so for t min 11.5 μs

R = $\frac{11.5}{0.227\times ln(\frac{5.03}{0.833})}$

R min = 28.173 ohm

and

for t max 6.33 ms

R max = $\frac{6.33}{11.5} \times 28.173$

R max = 1.55 × $10^{4}$ ohm

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3 years ago

A large retail organization previously divided work among its four employee benefits staff into distinct specializations. One pe

denpristay [2]

Answer:

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Explanation:

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3 years ago