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storchak [24]
3 years ago
9

Consider the same rectangle of the preceding 8 units. Squares of x by x units are cut out of each corner, and then the sides are

folded up to create an open box. Express the volume of the box as a polynomial function in terms of x problem. Squares of 2x by 2x units are cut out of each corner. Express the volume of the box as a polynomial in terms of x.
Mathematics
1 answer:
GuDViN [60]3 years ago
7 0

Answer:

V(x) = l*w*x  - 2*l*x² - 2*w*x² + 4*x³

Step-by-step explanation:

The volume of any box is:

a * b * h       where a is the length, b is the wide and h is the height

Assuming we have cardboard of dimensions: l * w

l - 2*x  will be length  of the box and  

w - 2*x will be wide of the box

h  =  x the height, then:

V(x) = ( l  -  2*x  ) *  (  w  -  2*x ) * x

V(x) = [ ( l*w - 2*l*x - 2*w*x + 4*x² ] * x

V(x) = l*w*x  - 2*l*x² - 2*w*x² + 4*x³

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Solve the following system using substitution. Remember to record your answer as (x, y).
natta225 [31]

Answer:

You already have what you are going to substitute, just put the y values from the first equation into the second! Like this:

6x - 5(-2x - 9) = -19

Multiply it out:

6x +10x +45 = -19

Add like terms + simplify:

16x + 45 = -19

16x = -64

x = -4

take that x and put it back into the first equation!!

y = -2(-4) -9

y= 8-9

y= -1

so... your answer is (-4, -1)

hope this helps!

4 0
3 years ago
So i had a 95 in math but then my teacher wanted to drop it to a 45 because she thought something was missing but now how do i b
Amiraneli [1.4K]

Answer:

just ask

Step-by-step explanation:

ask your teacher what am I missing i felt like I had everything done what am i not turning in

5 0
3 years ago
Determine which postulate or theorem can be used to prove that
EleoNora [17]

Answer:

\triangle ABC \cong \triangle DCB by <u>AAS</u>

Step-by-step explanation:

According to the following two triangles, \triangle ABC and \triangle DCB are congruent by <u>Angle-Angle-Side</u> (AAS), because there are two angles shown and share a side, which is in the middle between triangles.

7 0
4 years ago
Help me out please
saul85 [17]

The surface area of the geometric shape is B. 840 cm².

Step-by-step explanation:

Step 1:

The given figure is made up of three rectangles and two triangles.

The surface area of the geometric shape is given by summing the individual surface areas.

The geometric shape's surface area = The sum of the individual surface areas.

Step 2:

The surface area of the rectangles is the multiplication of its length and width.

The surface area of the rectangle with length z and width x = (26)(10)= 260 cm^{2}.

The surface area of the rectangle with length y and width x = (24)(10)= 240 cm^{2}.

The surface area of the rectangle with length x and width x = (10)(10)= 100 cm^{2}.

Step 3:

The area of a triangle is half the product of its base length and height.

The surface area of a triangle with base y and height x= \frac{1}{2} (24)(10) = 120 cm^{2}.

They are two similar triangles so their areas are equal

Step 4:

The geometric shape's surface area = 160 + 240+100+120+120 = 840 cm^{2}.

So the surface area is option B. 840 cm².

5 0
3 years ago
A cubed-shaped box has its side lengths decreased by 3 cm, when this happens, the volume decreases by 1385cm^3. What is the side
mixer [17]

Answer:

Step-by-step explanation:

let side of cube=x cm

volume=x³ cm³

again side=(x-3) cm

volume=(x-3)³ cm³

x³-(x-3)³=1385

(a³-b³)=(a-b)(a²+ab+b²)

(x-x+3){x²+x(x-3)+(x-3)²}=1385

3(x^2+x²-3x+x²-6x+9)=1385

3(3x²-9x+9)=1385

9x²-27x+27=1385

9x²-27x+27-1385=0

9x²-27x-1358=0

x=\frac{27\pm\sqrt{(-27)^2-4*9*(-1358)} }{2*9} \\x=\frac{27\pm\sqrt{729+48888} }{18} \\or~x=\frac{27\pm\sqrt{49617} }{18} \\or~x=\frac{27\pm 222.749}{18} \\taking positive side only as negative sign gives negative length.\\or~x=\frac{27+222.749}{18} \\or~x\approx13.87

3 0
3 years ago
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