Answer:
18 students
Step-by-step explanation:
90 percent of 20 is 18. 75 percent of 20 is 15.So More than 15 students .
The total surface area of the can of coke is 641.143 cm².
<h3>What is the total surface area of the can?</h3>
A can of coke has the shape of a cylinder. A cylinder is a three-dimensional object that is made up of a prism and two circular bases. The total surface area of a closed cylinder can be determined by adding the area of all its faces.
Total surface area of the closed cylinder = 2πr(r + h)
Where:
- r = radius = 6cm
- h = height = 11 cm
- r = pi = 22 / 7
Total surface area of the closed cylinder = (2 x 22/7 x 6) x (6 + 11)
(264 / 7) x (17)
37.714 x 17 = 641.143 cm²
To learn more about how to calculate the total surface area of the closed cylinder, please check: brainly.com/question/13952059
#SPJ1
Answer:
Shifted left by 2 units
Step-by-step explanation:
When you have a function (say f(x)), you can translate it left or right by replacing what's inside the function. In this case it is shown that the x in f(x) is replaced with x+2 in g(x). Therefore:
Rewriting g(x) like this shows that there is a +2 in the f(x). Whenever there is a number being added inside the function, then the graph is shifted left that many units (and vice versa for subtraction). So in this case since 2 is being added inside the function the graph will be translated left 2
The fraction form 4/7 and the decimal form is 0.571428
Answer:
1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))
Step-by-step explanation:
1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))
