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NemiM [27]
4 years ago
9

3.0 L of a gas is at a temperature of 78 degrees Celsius. Find the volume of the gas at standard temperature

Chemistry
1 answer:
Vesna [10]4 years ago
7 0

Answer:

= 2.33 L

Explanation:

Using the Charles law.

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

    = 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

     = (3.0 ×273)/351

     <u>= 2.33 L</u>

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