The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:
Percent error = |Measured Value - True Value|/True Value * 100
The || is needed to get the absolute value of the difference. Substituting the values,
Percent error = |(10.085 g/10 mL) - 0.9975 g/mL|/<span>0.9975 g/mL * 100
</span><em>Percent error = 1.1% </em>
Answer:
See below
Step-by-step explanation:
1. Colloid
B) Microscopic insoluble particles that are suspended throughout another substance.
Milk is a colloid. It consists of small fat globules suspended in water.
2. Emulsion
D) Two or more liquids that are not normally mixable.
Mayonnaise is an emulsion. It consists of oil, egg yolks, vinegar, and seasonings. Normally, the oil and vinegar (95 % water) do not mix. Without the egg yolk , they would quickly separate. Egg yolk contains the emulsifier, lecithin, which is attracted to both oil and water and stabilizes he mixture.
3. Solution
A) A solute that is evenly distributed within the solvent.
Sugar syrup is a solution of sugar in water.
4)Homogeneous
C) A mixture that has its components distributed evenly within the substance.
A homogeneous mixture has only one phase. For example, the sugar syrup is homogeneous, because, even with a powerful microscope, you can't see a boundary between the sugar particles and the water.
Answer:
2.893 x 10⁻³ mol NaOH
[HCOOH] = 0.5786 mol/L
Explanation:
The balanced reaction equation is:
HCOOH + NaOH ⇒ NaHCOO + H₂O
At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.
The moles of base added is calculated as follows:
n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH
Extra significant figures are kept to avoid round-off errors.
Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.
(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH
The concentration of HCOOH to the correct number of significant figures is then calculated as follows:
C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L
The question also asks to calculate the moles of base, so we convert millimoles to moles:
(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH
Answer:
C
Explanation:
The Eukaryotic pre-mRNA receives a 5' cap and 3'poly(A) tail before Introns are removed and the mRNA is considered ready for translation.
