The chip, during the collision, has a change in momentum:
Δp = m · (v₂ - v₁)
The final speed is equal to zero, since it sticks to the spacecraft, therefore:
Δp = m · v
= 1.6×10⁻⁷ · 3×10³
= 4.8×10⁻⁴ kg·m/s
where we transformed the mass into the proper units of measurement (kg).
This change in momentum is equal to the impulse J:
Δp = J = F · t
We can solve for F
F = J / t = <span>Δp / t
= </span>4.8×10⁻⁴ / 6×10⁻⁸
= 8.0×10³ N
Hence, <span>the force exerted by the chip on the spacecraft is F = 8000N.</span>
Answer:15,883.63 KJ
Explanation:
Given
Power=400 W
Freezing compartment temperature is 273 K
Outside air Temperature=306 K
Time =80 minutes
Energy Required to deliver 400 w power in 80 minutes
E=1920 KJ
and we know COP of refrigerator is given by
Therefore 15,883.63 KJ is removed in 80 minutes
Answer: 4 herz is the answer!
Explanation:
