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Furkat [3]
3 years ago
12

A doctor counts 68 heartbeats in 1.0 minute. What are the corresponding period and frequency of the heart rhythm

Physics
1 answer:
sergejj [24]3 years ago
8 0

Answer:

f=1.13s^{-1}=1.13Hz

Explanation:

Hello,

In this case, a frequency stands for a rate in which some action is done per unit of time. In this case, for the heartbeat, since 68 actions (heartbeats) occur in 1.0, the frequency turns out:

f=\frac{68}{1.0min}=68min^{-1}

Or as most commonly used in Hz (s^{-1}):

f=68\frac{1}{min} *\frac{1min}{60s}=1.13s^{-1}=1.13Hz

Best regards.

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A 60kg student traveling in a 1000kg car with a constant velocity has a kinetic energy of 1.2 x 10^4 J. What is the speedometer
777dan777 [17]

Answer:

17.64 km/h

Explanation:

mass of car, m = 1000 kg

Kinetic energy of car, K = 1.2 x 10^4 J

Let the speed of car is v.

Use the formula for kinetic energy.

K = \frac{1}{2}mv^{2}

By substituting the values

1.2\times 10^{4} = \frac{1}{2}\times 1000\times v^{2}

v = 4.9 m/s

Now convert metre per second into km / h

We know that

1 km = 1000 m

1 h = 3600 second

So, v = \left (\frac{4.9}{1000}   \right )\times \left ( \frac{3600}{1} \right )

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3 years ago
Use the motion map to answer the question.
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Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

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3 years ago
Question 4
bagirrra123 [75]

That's <em>false</em>.  It's just the opposite.  As you become more fit, your heart becomes able to accomplish more with each beat, so your resting heart rate DEcreases.

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A new cat 6 cable run and key stone jack were installed for a workstation that was moved from the sales department to the shippi
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The cable run exceeds the specifications for Ethernet over twisted pair

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A truck of mass 1800kg is moving with a speed 54km/h. When brakes are applied, it
EleoNora [17]

Force = 3200 N

Work done = 640, 000 Nm

Explanation:

We begin by calculating the deceleration of the truck, using the velocity and distance;

a = (v² – u²)/2s

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a = acceleration

v = initial velocity

u = initial velocity

s = distance

We begin by changing the speed from km/h into m/s;

54km/hr = 15m/s

Then acceleration;

a = (0² – 15²) / 2 * 200

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To calculate force;

F = ma

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F = force

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a = acceleration

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F = 3200 N

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