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Lynna [10]
3 years ago
13

A car traveling at 21 m/s starts to decelerate steadily. It comes to a complete stop in 13 seconds. What is its acceleration?

Physics
1 answer:
diamong [38]3 years ago
6 0

The formula for acceleration is the velocity times the inverse of time so it would be 21 times 1/13. So roughly 0.0769... is the acceleration(m/s^2).

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Answer:

A. The time taken for the car to stop is 3.14 secs

B. The initial velocity is 81.64 ft/s

Explanation:

Data obtained from the question include:

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

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A. Determination of the time taken for the car to stop.

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Velocity (V) = distance (s) /time (t)

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Acceleration (a) = 26ft/s2

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V = U + at

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0 = U – 81.64

Collect like terms

U = 81.64 ft/s

Therefore, the initial velocity is 81.64 ft/s

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