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Tamiku [17]
3 years ago
11

What is a neutralisation reaction? Give two examples.

Chemistry
1 answer:
ozzi3 years ago
7 0

Explanation:

A neutralization is a type of double replacement reaction. a salt is the product of an acid-base reaction and is a much broader term then common table salt.

Example:-

(i) HCl + NaOH ---> NaCl + HOH

(ii) H2SO4 + 2NH4OH ---> (NH4)2SO4 + 2HOH.

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A sample of oxide iron weighing 2.40g was heated in a stream of hydrogen until it was completely converted to the metal. If the
wlad13 [49]

Answer:

Fe₂O₃

Explanation:

To solve this question we must find the moles of Iron in 1.68g. With the difference of the masses we can find the moles of oxygen. The formula will be obtained with the ratio of both amount of moles:

<em>Moles Fe:</em>

1.68g * (1mol / 56g)  =0.03moles

<em>Moles O:</em>

2.40g-1.68g = 0.72g * (1mol/16g) = 0.045moles

The ratio O/Fe is:

0.045moles / 0.03moles = 1.5 moles. this ratio is obtained if the formula is:

<h3>Fe₂O₃</h3>
4 0
3 years ago
List the following molecules in order of increasing boiling point: Br2, Cl2, F2, I2.
Andrej [43]

Answer:

1. None of these have hydrogen bonding.

2. None of these have dipoles.

3. Bigger molecules will have stronger London dispersion forces. So I2 has the strongest forces,

and F2 will have the weakest. Correspondingly, I2 will have the highest boiling point and F2 will have the lowest boiling point.

Answer: F2, Cl2, Br2, I2

Explanation:

7 0
3 years ago
Read 2 more answers
76.0 mol of P4O10 contains how many moles of P?
NikAS [45]
For a mole of P4O10, there are 4 moles of P. Hence for 76 moles of P4O10, the number of P moles is a total of 304. 
8 0
3 years ago
Read 2 more answers
The price of gold is $40.63/g. How many kg of gold would be worth $100?
lora16 [44]

Answer:

0.00246kg

Explanation:

1g = $40.63

$100 = $100/40.63 = 2.46g

2.46/1000 g = 0.00246kg

3 0
3 years ago
The heat capacity of liquid water is 4.18 J/g·°C and the heat of vaporization is 40.7 kJ/mol. How many kilojoules of heat must b
pychu [463]

Answer:

The correct answer would be - 2.4KJ or, 2400J

Explanation:

Given:

heat capacity of liquid water - 4.18 J/g·°C

heat of vaporization - 40.7 kJ/mol

Mass of water = 1g

Moles of water = mass/molar mass

= 1g/18.016g

= 0.055 moles

Then,

Total heat required = q1(to raise the temperature to 100) + q2(change from the liquid phase to gas/steam)

= m *s*dt + moles * heat of vaporization

= (1g * 4.18 j/gc * (100-67)) + 0.055* 40.7 KJ

= 137.94J + 2.26KJ

=0.138KJ + 2.26KJ

=2.4KJ or, 2400J

Thus, the correct answer would be - 2.4KJ or, 2400J

3 0
4 years ago
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