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Tamiku [17]
3 years ago
11

What is a neutralisation reaction? Give two examples.

Chemistry
1 answer:
ozzi3 years ago
7 0

Explanation:

A neutralization is a type of double replacement reaction. a salt is the product of an acid-base reaction and is a much broader term then common table salt.

Example:-

(i) HCl + NaOH ---> NaCl + HOH

(ii) H2SO4 + 2NH4OH ---> (NH4)2SO4 + 2HOH.

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Just make it sound right please it don't even add up what was you even thinking like come on now...lol

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What does this mean I don't understand your question.

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3 years ago
The equivalence point in a titration refers to the point when
azamat

Answer:

C) the number of moles of one reactant reacts completely with the moles of the other reactant.

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it's right put it

8 0
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Wind erosion occurs at a faster rate in the desert then in place of the pacific layer of vegetation covering the ground why do y
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6 0
4 years ago
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In the periodic table how many elements could be classified as metals in group IV?
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4 elements are classified in group 4 like titanium, zirconium, hafnium and ruthorfordium
8 0
4 years ago
A compound contains 64.27% carbon, 7.19% hydrogen, and 28.54% oxygen. the molar mass is 168.19 g/mol. what is the molecular form
coldgirl [10]
Empirical formula is the simplest ratio of whole numbers of components in a compound 
calculating for 100 g of compound 
                                             C                             H                             O
mass                                  64.27 g                   7.19 g                     28.54 g
number of moles        64.27 g / 12 g/mol      7.19 g/1 g/mol     28.54 g / 16 g/mol 
                                        = 5.356 mol           = 7.19 mol           = 1.784 mol 
divide by least number of moles  
                                     5.356 / 1.784            7.19 / 1.784         1.784 / 1.784
                                      = 3.002                     4.03                     = 1.000
rounded off to nearest whole number 
 C - 3
 H - 4
 O - 1
empirical formula - C₃H₄O
 
 mass of empirical formula = 12 g/mol  x 3 + 1 g/mol x 4 + 16 g/mol x 1 = 56 g
molecular mass = 168.19 g/mol 
molecular formula is the actual ratio of elements making up the compound 
number of empirical units = molar mass of molecule / empirical mass
      empirical units = 168.19 g/mol  / 56 g = 3.00
there are 3 empirical units making up the molecular formula 
molecular formula = 3 x C₃H₄O

molecular formula = C₉H₁₂O₃

                 
5 0
4 years ago
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