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dimulka [17.4K]
3 years ago
9

Triangle ABC is reflected over the x-axis when is the coordinate for C?

Chemistry
1 answer:
Assoli18 [71]3 years ago
4 0
(1,2 because c is already on the other side so you have to reverse it
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A compound of low solubility
fenix001 [56]

Answer:

b. is always a weak electrolyte.

Explanation:

Such compounds of low solubility dissociates partly and hence cannot be strong electrolytes

4 0
3 years ago
H 2 O, CO 2 , and C 12 H 22 O 11 are all examples of chemical _____.
Reil [10]
They are all examples of chemical formulas
6 0
3 years ago
Read 2 more answers
the mass of a liquid is 11.50 g and its volume is 9.03 mL. How many significant figures should its density value have?
BlackZzzverrR [31]

Answer:

3

Explanation:

The mass has 4 sig digits.

The volume has 3 sig digits

The density is = 11.50/9.03 = 1.2735

To 3 sig digits (determined by 9.03) the answer would be 1.27 gram/mL

6 0
3 years ago
The rate of a certain reaction is given by the following rate law: rate Use this information to answer the question below. At a
AleksAgata [21]

Answer:

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

Explanation:

N_2+3H_2\rightarrow 2NH_3

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Initial rate of the reaction = R = 4.0\times 10^5 M/s

R = k\times [N_2][H_2]^3

4.0\times 10^5 M/s=k\times [N_2][H_2]^3

The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

[H_2]'=2[H_2]

R'=k\times [N_2][H_2]'^3=k\times [N_2][2H_2]^3

R'=8\times k\times [N_2][H_2]^3

R'=8\times R=8\times 4\times 10^5 M/s=3.2\times 10^6 M/s

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

7 0
4 years ago
4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate
Alona [7]

Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

Initial temperature = 23.0°C

Final temperature = 57.8°C

Specific heat capacity of water = 1 cal/g.°C

Mass of water in gram = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

m = 4450 g

4 0
3 years ago
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