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Sav [38]
3 years ago
12

Question 9 (1 point)

Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

8 moles of C

Explanation:

From the question given above, the following equation was obtained:

3A + 2B —> 6C

From the equation above,

3 moles of A reacted to produce 6 moles of C.

Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:

From the equation above,

3 moles of A reacted to produce 6 moles of C.

Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C

Thus, 8 moles of C can be obtained from the reaction of 4 moles of A with excess B

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Consider the following balanced equation for the following reaction:
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<u>Answer:</u> The actual yield of the carbon dioxide is 47.48 grams

<u>Explanation:</u>

For the given balanced equation:

15O_2(g)+2C_6H_5COOH(aq.)\rightarrow 14CO_2(g)+6H_2O(l)

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Theoretical moles of carbon dioxide = 1.30 moles

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

1.30mol=\frac{\text{Theoretical yield of carbon dioxide}}{44g/mol}\\\\\text{Theoretical yield of carbon dioxide}=(1.30mol\times 44g/mol)=57.2g

To calculate the theoretical yield of carbon dioxide, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Theoretical yield of carbon dioxide = 57.2 g

Percentage yield of carbon dioxide = 83.0 %

Putting values in above equation, we get:

83=\frac{\text{Actual yield of carbon dioxide}}{57.2}\times 100\\\\\text{Actual yield of carbon dioxide}=\frac{57.2\times 83}{100}=47.48g

Hence, the actual yield of the carbon dioxide is 47.48 grams

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