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Pavlova-9 [17]
3 years ago
14

Help pls pls pls I really need this answer

Chemistry
1 answer:
blagie [28]3 years ago
5 0

Answer:

I never did this but i think its d 37.5٪ lmk if i got it right pls and srry if i didnt

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If Santa Claus is in the beach then what will you call him?​
ahrayia [7]

Answer:

good question..... lemme think now LOL

6 0
3 years ago
Nitrogen-fixing bacteria live in protective nodules (bumps) on the roots of some plants. These bacteria are able to convert gase
Vsevolod [243]
I believe it is A because the plant is offering protection while the bacteria is converting it in to nitrogen that the plant can use!
3 0
3 years ago
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Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
8 0
3 years ago
How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?
docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

Initial temperature = 52.0 °C

Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

6 0
3 years ago
A note about crystallization or its definition?
Mashutka [201]
Crystallization is: A chemical of solid - liquid separation technique, in which mass transfers a solute from the liquid solution to a pure solid crystalline phase occurs. In chemical engineering crystallization occurs in a crystallizer.

Hope I helped!

- Debbie
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4 0
3 years ago
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