Answer:
1 billion
Explanation:
The computation of the number of atoms for C-14 is shown below:
Because it is mentioned
Half the isotope for carbon 14 is 5,730 years
Currently if there had been 4 billion it would equate to 2 billion
Now that the 2 billion would've been 1 billion in the next 5,730 years
And it'll become 3 half-life
Therefore the number of C-14 atoms is 1 billion
<span>An atom's identity, that is, whether it is 'oxygen' or 'plutonium', for example, is determined solely by the number of protons in the nucleus. The number of neutrons also plays a part - a differing number of neutrons can change an atom from one isotope of an element into another, but the atoms would still remain the same element, albeit a different isotope. The number of electrons orbiting the atom does not change the identity of the atom, only it's electronic state. Take electrons away and it becomes a positively charged ion of the same element. Add electrons and it becomes a negatively charged ion, but still of the same element.</span>
Answer:-
190.23 gram mol-1
Explanation:-
Molar mass is the mass of 1 mole of that substance. It's unit is gram / mol or gram mol-1.
For an element it is equal to it's atomic weight.
The atomic weight of Osmium is 190.23
Hence the molar mass of Osmium is 190.23 gram / mol
Answer:
6 moles
Explanation:
Take a look at the balanced chemical equation for this synthesis reaction
N
2(g]
+
3
H
2(g]
→
2
NH
3(g]
Notice that you have a
1
:
3
mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.
So, if you have
2
moles of nitrogen taking part in the reaction, you will need
2
moles N
2
⋅
3
moles H
2
1
mole N
2
=
6 moles H
2
The half-reaction are:
Cd ---> Cd(OH)₂
The oxidation number of Cd changed from 0 to +2. So, the number of mol electron transferred here is 2.
NiO(OH) --> Ni(OH)₂
The oxidation number of Cd changed from +3 to +2. So, the number of mol electron transferred here is 1.
Now, the greatest common factor would be 2. So, we use n=2 for the formula for ΔG°. F is Faraday's constant equal to 96,485 J/mol e.
ΔG° = nFE° = (2)(96,485)(1.5) =<em> 289,455 J</em>