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3 years ago

-12x = 4 What’s the Answer?

Mathematics

2 answers:

disa [49]3 years ago

7 0

Answer:

The answer is -1/3.

Step-by-step explanation:

To get x alone, you would have to divide both sides by -12, which would leave you with x = -4/12. However, -4/12 simplified = -1/3.

Serjik [45]3 years ago

3 0

Answer: exact form Is - 1 over 3

decimal form is -0.3

Step-by-step explanation:

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Cos 4A - cos 4B = 8(cos A - cos B) (cos A +cos B) (cos A - sin B) (cos A + sin B)

sveta [45]

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3 years ago

What is greater, 3/5r 4/10?

DanielleElmas [232]

3/5 = .6 and 4/10 = .4, so 3/5 is greater than 4/10

7 0

3 years ago

Chloe drew a triangle with side lengths of 30 centimeters, 24 centimeters, and 18 centimeters. Juan drew a triangle with side le

vlada-n [284]

Answer:

A and B

Step-by-step explanation:

Each side in Chloe's triangle is 1.5 times the length of each side in Juan's triangle. Thus, they are 'similar' by the <u>math </u>definition of that word, by the SSS Rule for Similar Triangles.

That means they are different only in size. So, their angle measures are the same and they are the same shape.

A and B are true.

C is never true, because the sum of all 3 angles in a triangle is always 180°.

D is not true, because they are similar.

5 0

3 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago

Can you guys help me please.

Norma-Jean [14]

Answer:

question 1: answer is 4

question 2: answer is 1

Step-by-step explanation:

6 0

3 years ago