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siniylev [52]
3 years ago
13

you fill up 40 gallon pool putting in 2 gallons water every minute, if someone scoops out 1 gallon every 8 minutes, how long wou

ld it take to fill the pool?
Mathematics
2 answers:
Sav [38]3 years ago
5 0
There's a catch here, and I don't really want to go into full detail.  Because of
this catch, I think it would be unusually tough to write a simple equation for this
situation. If you wouldn't mind, let's just list it instead:

<u>After</u> . . <u>water added</u> . . <u>total in pool</u>

7 min . . . 14 gallons . . . 14 gallons
1 more . . 1 gallon . . . . . 15 gallons
7 more . . 14 gallons . . . 29 gallons
1 more . . 1 gallon . . . . . 30 gallons
5 more . . 10 gallons . . . 40 gallons, the pool is full

Add up all the minutes: <u>21 minutes</u>
natta225 [31]3 years ago
4 0
It would take 21 minutes
As the first 8 minutes there would be 15 gallons in the pool
In 16 minutes there would be 30 gallons in the pool
Therefore you only need 10 gallons left which will be filled up in the space of 5 minutes
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Write the equation of the line in fully simplified slope intercept form
Naily [24]

Answer:   y = (1/4)x - 1

Step-by-step explanation:

Slope intercept form is y = mx + b. The y-intercept is -1 so we have y = mx - 1. To find m, look at the points (0, -1) and (4, 0). The line goes up 1 and over 4, so the slope, m, equals 1/4. Thus the full equation is

$y = (1/4)x - 1.

4 0
2 years ago
A company introduces a new product for which the number of units sold S is
KonstantinChe [14]
(a) The "average value" of a function over an interval [a,b] is defined to be 

(1/(b-a)) times the integral of f from the limits x= a to x = b. 

Now S = 200(5 - 9/(2+t)) 

The average value of S during the first year (from t = 0 months to t = 12 months) is then: 

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12 

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12 

This equals 200/12 * (5t -9ln(2+t)) 

Evaluating this with the limits t= 0 to t = 12 gives: 

708.113 units., which is the average value of S(t) during the first year. 


(b). We need to find S'(t), and then equate this with the average value. 

Now S'(t) = 1800/(t+2)^2 

So you're left with solving 1800/(t+2)^2 = 708.113 

<span>I'll leave that to you</span>
6 0
3 years ago
A sleep time of 15.9 hours per day for a newborn baby is at the 10h percentile of the distribution of sleep times for all newbor
Step2247 [10]

The mean time in hours per day for newborn babies is 16.5 hours ⇒ D

Step-by-step explanation:

A sleep time of 15.9 hours per day for a newborn baby is at the 10th

percentile of the distribution of sleep times for all newborn babies

Assuming the distribution is normal with a standard deviation of

0.5 hour

To find the mean time let us do that

1. Use the normal distribution table to find the corresponding z-score

   for 10th percentile

2. Use the rule μ = x - zσ, where μ is the mean, σ is the standard

    deviation and x is the score

3. Substitute the values of x, σ and z in the rule to find μ

Look to the normal distribution table to find z-score that equivalent

to the area = 10/100 = 0.1 (10th percentile)

∵ z-score = -1.28

∵ σ = 0.5 hour

∵ x = 15.9

∵ μ = x - zσ

- Substitute the values in the rule

∴ μ = 15.9 - (-1.28)(0.5)

∴ μ = 15.9 + 0.64

∴ μ = 16.54 ≅ 16.5 hours

The mean time in hours per day for newborn babies is 16.5 hours

Learn more:

You can learn more about the normal distribution curve in brainly.com/question/8799684

#LearnwithBrainly

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%2064%20%7D%20" id="TexFormula1" title=" \sqrt{ - 64 } " alt=" \sqrt{ - 64 }
Kipish [7]
What’s the other number?
3 0
3 years ago
What is the length of the hypotenuse, c? Round your answer to the nearest hundredth.
Afina-wow [57]

Answer:

Step-by-step explanation:

By using the Pythagorean theorem:

b^2+3^2=5^2
b^2+9=25

b=sqrt (25-9)

b=sqrt(16)

b=4

=> 4^2+7^2=c^2
16+49=c^2
65=c^2
=>c=sqrt(65)

c = (approximately) 8

5 0
2 years ago
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