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Vlada [557]

3 years ago

for x if 4 x+1-9(2 ^{2} +2=0" alt="solve for x if 4 x+1-9(2 ^{2} +2=0" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

Answer:

4×+1-9 (2^)+2)=0

4×+1-9 (4+2)=0

4×+1(-36-18)=0

4×+1 (-54)=0

4×-54=0

4×=54

×=54÷4

×=13.5

Dima020 [189]3 years ago

4 0

Answer:

mark my answer as the brainliest

Step-by-step explanation:

x = 53/4

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve the equation in the complex number system. x^2-12x+40=0

mylen [45]

solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Step-by-step explanation:

Solve the equation:

$x^2-12x+40=0$

We can solve using quadratic Formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

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Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i$

So, solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Keywords: Solving quadratic equation

Learn more about Solving quadratic equation at:

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Help with this please. I’d appreciate if you showed the steps and the answer. Thanks!

olga55 [171]

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A merchant buys a television for $125 and sells it for $75 more.What is the percent of markup?

cestrela7 [59]

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