Answer:
38 m/s
43 m/s
Explanation:
x = 18t + 5.0t²
The instantaneous velocity is the first derivative:
v = 18 + 10.t
At t = 2.0:
v = 18 + 10.(2.0)
v = 38 m/s
The average velocity is the change in position over change in time.
v = Δx / Δt
v = [ (18t₂ + 5.0t₂²) − (18t₁ + 5.0t₁²) ] / (t₂ − t₁)
Between t = 2.0 and t = 3.0:
v = [ (18(3.0) + 5.0(3.0)²) − (18(2.0) + 5.0(2.0)²) ] / (3.0 − 2.0)
v = [ (54 + 45) − (36 + 20.) ] / 1.0
v = 99 − 56
v = 43 m/s
<span>When you are setting up your budget, it is easier to start by setting your budgeting amounts based on the average of your last three months of spending. Many budgeting programs can import past transactions and help you come up with the estimates that you need for your budget. Then you can begin to make adjustments after you have those initial amounts.
</span>
The two main goals are to spend less than you earn and to know where your money is going. Once you have a working budget you can work towards your other goals of saving money and getting out of debt. It is important to avoid theses common budgeting mistakes <span>when setting up your budget.
</span>
Answer:
Energy implies as the object’s capability to perform work. It is something that cannot be created or destroyed but can only be transformed. An object loses its energy, when it performs work, whereas it gains energy when the work is performed on it. Energy is broadly classified as kinetic energy and potential energy. While kinetic energy is the energy which an object contains because of a particular motion.
On the other hand, potential energy is the stored energy, because of its state of rest. As both the two forms of energy are measured in joules, people get easily confused between these two. So, take a read of the article which will help you to understand the differences between kinetic and potential energy.
Explanation:
Hope this helps - Good luck ^w
Answer:
E = k λ₀ / x₀, the field is in thenegative direction of the x axis (-x)
Explanation:
In this problem the electric field of a line of charge is requested, the expression for the electric field is
E = k ∫ dq / r²
where k is the Coulomb constant that you are worth 9 10⁹ N m²/C², that the charge and r the distance to the point of interest, in this case it is the origin (x = 0)
let's use the definite linear density
λ₀ = dq / dx
dq = λ₀ dx
we replace and integrate
E = k λ₀ ∫ dx / x²
E = k λ₀ ( -1 / x)
we evaluate the integral from the lower limit of load x = x₀ to the upper limit x = ∞
E = - k λ₀ (1 /∞ - 1 / x₀)
E = k λ₀ / x₀
as the field is positive the direction is away from the charges, so it is in the negative direction of the x axis (-x)
Answer:
F₁> F₂
Explanation:
For this exercise Newton's second law is used, in the adjoint we can see the unapplied forces in this exercise.
Y axis y
N- W = 0
in this axis there is no movement
X axis
F -fr = m a
as they indicate that the velocity is consonant the acceleration is worth zero
F - fr = 0
friction force has the expression
fr = μ N
fr = μ mg
we substitute
F = μ m g
by the time the block is stopped the deferred force is
F₁ = μ_s m g
when it begins to move the force should decrease to
F₂ = μ_k k m g
as the static coefficient is greater than the dynamic coefficient
F₁> F₂