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Vikki [24]
3 years ago
12

What is the least value of an ammeter Is it 1. 0.12. 0.103. 0.24. 0.5​

Physics
1 answer:
givi [52]3 years ago
3 0

The least value varies depends on ammeter range. In the given question, ammeter range is not mentioned. So, the least value of an ammeter is 0.1 or 0.5 (depends on ammeter range).

<u>Explanation:</u>

The least value of an ammeter is the measure of the smallest number which can be observed in ammeter. So the least value will be varying depending upon its range. If we consider the range of ammeter is 30 A and the scale readings are 10 numbers, then the least value will be 30/10 = 3 A per scale.

So the least value is determined as \frac{Range of ammeter}{No.of scales}

So among the given options 0.1 is most suitable for an ammeter with range of 3 A with 30 divisions.

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Alla [95]

Answer:

q=1\times10^{-8}C

Explanation:

Let the charge on the ball bearing is q.

charge on glass bead, Q = 20 nC = 20 x 10^-9 C

Force between them, F = 0.018 N

Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

F=\frac{KQq}{d^{2}}

By substituting the values

0.018=\frac{9\times10^{9}\times20\times10^{-9}q}{0.01^{2}}

q=1\times10^{-8}C

Thus, the charge on the ball bearing is q=1\times10^{-8}C

7 0
3 years ago
A steel rod has a diameter of 3.75cm.Express it's diameter in millimeters and meter
romanna [79]

Answer:

3.75cm into millimetres

= 3.75 * 10

37.5 millimetres

3.75 cm into metres

3.75/100

= 0.0375m

6 0
3 years ago
Children make toy telephones by sticking each end of a long string through a hole in the bottom of a paper cup and knotting it s
Darina [25.2K]

Answer:

The bottom of the cup passes the sound waves to the string, and so on to the other cup. You can hear surprisingly far using a string telephone if help the right way! If the string is kept tight, the sound waves will travel.

Explanation:

3 0
3 years ago
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A ball is dropped from an aircraft flying at an altitude of 8,848 meters assuming gravity is 9.8m/s what is the total amount of
Dafna11 [192]
In this question, you're determining the time (t) taken for an object to fall from a distance (d).

The equation to represent this is:
Time equals the square root of 2 times the distance divided by the gravitational force of earth.
In equation from it looks like this (there isn't an icon to represent square root so just pretend like there's a square root there):
t = 2d/g (square-rooted)

d = 8,848m and g = 9.8m/s

Now plug in the information we have:
t = 2 x 8,848m/9.8m/s (square-rooted)

The first step is to multiply 2 times 8,848m:
t = 17,696m/9.8m/s (square-rooted)

Now divide 9.8m/s by 17,696m (note that the two m's (meters) cancels out leaving you with only s (seconds):
t = 1805.72s (square-rooted)

Now for the last step, find the square root of the remaining number:
t = 42.5s

So the time it takes the ball to drop from the height (distance) of 8,848 meters, and falling with the gravitational pull of 9.8 meters per second is 42.5 seconds.

I hope this helps :)

7 0
3 years ago
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1,000 milligrams = 1 gram
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4 years ago
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