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3 years ago

Which type of path do planets follow around the sun?

Physics

2 answers:

kolbaska11 [484]3 years ago

7 0

<u>Answer:</u>

The correct answer option is A) Ellipse.

<u>Explanation:</u>

A curve in a plane which is surrounded by the two focal points such that the sum of the distances between the two focal points is constant for each of the points on the curve, is called an ellipse.

The planets in the space around the sun follow an elliptical path, with the Sun at one focus so the sum of the distances between the planets and the Sun remain the same.

Elza [17]3 years ago

4 0

A. ellipse...........

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A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav

gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

$K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

$v^2=v_o^2+2gy$

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

$v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}$

With this value you can find the spring constant k from the equation (1):

$mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}$

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

$W=F_e\\\\mg=kx$

you solve the last expression for x:

$x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m$

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

$v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}$

Next, you calculate x from the equation (1):

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m$

The net fire is stretched 2.72 m

5 0

3 years ago

I'm studying the equilibrium of forces so hard that I got confused for a sec. Is the force due to gravity included in summing up

jenyasd209 [6]

Answer:

Yes, you would consider the mass × gravity at the centre of gravity of the object in question to cause a moment, hence it should be included in your resolution

3 0

2 years ago

What are allotropes? Give an example.

VARVARA [1.3K]

Allotropes are different forms of the same element. Different bonding arrangements between atoms result in different structures with different chemical and physical properties. Allotropes occur only with certain elements, in Groups 13 through 16 in the Periodic Table.

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3 years ago

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How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Nuetrik [128]

a = ( V2 - V1)/( t2 - t1)
3.2 = ( 23.5m/s - 15.2m/s)/(t - 0)
3.2m/s = 8.3/t
t(3.2) = 8.3
t = 8.3/3.2
t = 2.59 seconds

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3 years ago

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What change will most likely increase the strength of a magnetic field produced by an electromagnet? a. Reduce the number of tur

Anettt [7]

Answer:

Option D

Explanation:

When another battery is added to the circuit, the power supplied through the coil and to the magnet becomes greater leading to stronger magnetic field lines being produced.

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3 years ago