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Bezzdna [24]
3 years ago
13

How are magnetic force and distance from an object related

Physics
2 answers:
guapka [62]3 years ago
6 0

Answer:

Magnetic force obeys an inverse square law with distance

Explanation:

Otrada [13]3 years ago
6 0
Magnetic force obeys an inverse square law with distance. ... If the distance between two magnets is doubled the magnetic force between them will fall to a quarter of the initial value. (F/4) If the distance between two magnets is halved the magnetic force between them will increase to four times the initial value.
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Write the products for the following neutralization reactions
madam [21]

Answer:

answer 3

Explanation:

5 0
2 years ago
A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c
OLga [1]

Answer:

66.5N

Explanation:

F = kx

Where F = force

K = spring constant

x = compression

Given

K = 950N/m

x = 7.0cm

F = ?

First convert the compression to meters .

7.0cm = 7.0 x 0.01

= 0.07 meters

Therefore

F = 950 x 0.07

= 66.5N

4 0
3 years ago
If the net force on an object stays the same but the mass of the object is doubled, what will happen to the
Sergio [31]

Answer:

The acceleration of the object decreases I think

Explanation:

5 0
2 years ago
John says that the value of the function cos[ω(t + T) + ϕ], obtained one period T after time t, is greater than cos(ωt + ϕ) by 2
Svetllana [295]

Answer:

No one is right

Explanation:

John Case:

The function cos(\omega t +\phi) is defined between -1 and 1, So it is not possible obtain a value 2\pi greater.  

In addition, if you  move the function cosine a T Value, and T is the Period,  the function take the same value due to the cosine is a periodic function.

Larry case:

Is you have f=1+cos(\omega t +\phi), the domain of this is [0,2].

it is equivalent to adding 1 to the domain of the f=1+cos(\omega t +\phi), and its mean that the function f=cos(\omega t +\phi), in general, is not greater than cos(\omega t +\phi).

3 0
3 years ago
A gas is compressed at constant temperature from a volume of 5.68 L to a volume of 2.35 L by an external pressure of 732 torr. C
Vlada [557]

Answer: The work done in J is 324

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

W=-P\Delta V=-P(V_2-V_1)

W = amount of work done = ?

P = pressure = 732 torr = 0.96 atm    (760torr =1atm)

V_1 = initial volume = 5.68 L

V_2 = final volume = 2.35  L

Putting values in above equation, we get:

W=-0.96atm\times (2.35-5.68)L=3.20L.atm

To convert this into joules, we use the conversion factor:

1L.atm=101.33J

So, 3.20L.atm=3.20\times 101.3=324J

The positive sign indicates the work is done on the system

Hence, the work done for the given process is 324 J

5 0
3 years ago
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