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dalvyx [7]
4 years ago
15

a solid circular shaft 150 mm diameter transmits a torque of 29820.586 N.m. find the maximum shear stress

Engineering
1 answer:
bezimeni [28]4 years ago
4 0

Answer:

45 Mpa

Explanation:

The maximum shear stress, \tau_{max}is given by

\tau_{max}=\frac {16T}{\pi d^{3}}

Where T is the torque and d is the diameter.

Substituting  29820.586 N.m for T and 0.15m for d then we obtain

\tau_{max}=\frac {16\times 29820.586}{\pi \times 0.15^{3}}=44999999.22\approx 45 Mpa

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You will create three classes, the first two being Student and LineAtOfficeHour. The instances of the first class defines a sing
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Answer:

Complete solution is given below:

Explanation:

//student class

class Student{

  private String firstname,lastname;

 

  //constructor

  Student(String first,String last){

      this.firstname=first;

      this.lastname=last;

  }

 

  //getters and setters

  public String getFirstname() {

      return firstname;

  }

  public void setFirstname(String firstname) {

      this.firstname = firstname;

  }

  public String getLastname() {

      return lastname;

  }

  public void setLastname(String lastname) {

      this.lastname = lastname;

  }

  //function to get the fullname of student

  public String fullName() {

      return this.firstname+" "+this.lastname;

  }

}

//class for line at office hour

class LineAtOfficeHour{

 

  private Student line[];

  private int N=0;

  private int back=0;

 

  //empty constructor

  LineAtOfficeHour() {

      line=new Student[5];

  }

  //parameterized constructor

  LineAtOfficeHour(Student st[]) {

      int i=0;

      line=new Student[5];

      while(i<st.length && i<5) {

          line[i]=st[i];

          i++;

      }

      this.N=i;

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      if(this.N==0)

          return true;

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          return false;

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  public boolean isFull() {

      if(this.N==5) {

          return true;

      }else

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  public int size() {

      return this.N;

  }

 

  //function to add a student to the line

  public void enterLine(Student s) {

      if(isFull())

          System.out.println("Line is full!!!!");

      else {

          line[++back]=s;

          this.N++;

      }

  }

  public Student seeTeacher() {

      Student result=null;

      if(this.N>=0) {

          result=line[0];

          int i=0;

          for(i=1;i<N;i++) {

              line[i-1]=line[i];

          }

          line[i-1]=null;

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  public static void main(String[] args) {

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}

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4 years ago
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