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4 years ago

a solid circular shaft 150 mm diameter transmits a torque of 29820.586 N.m. find the maximum shear stress

Engineering

1 answer:

bezimeni [28]4 years ago

4 0

Answer:

45 Mpa

Explanation:

The maximum shear stress, $\tau_{max}$ is given by

$\tau_{max}=\frac {16T}{\pi d^{3}}$

Where T is the torque and d is the diameter.

Substituting 29820.586 N.m for T and 0.15m for d then we obtain

$\tau_{max}=\frac {16\times 29820.586}{\pi \times 0.15^{3}}=44999999.22\approx 45 Mpa$

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