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topjm [15]
3 years ago
10

Nearly__________ of all serious occupational injuries and illnesses stem from overexertion of repetitive motion.a. 1/2b. 1/4c. A

lld. 1/3
Engineering
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

Nearly one-third (1/3) of all serious occupational injuries and illnesses stem from overexertion of repetitive motion.

Explanation:

Ergonomic (scientific study of human work) is a vital issue these days because more than one-third (1/3) of all serious occupational injuries and illnesses stem from overexertion of repetitive motion. That is more than 33% of all serious occupational injuries and illnesses.

Occupational Safety and Health Associated (OSHA) has recognized the need to develop standards to help prevent ergonomic injuries and illnesses.  

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State the number of terms for each of the following algebraic expression 2x+1
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Answer:

Expressions are made up of terms.

A term is a product of factors.

Coefficient is the numerical factor in the term

Before moving to terms like monomials, binomials, and polynomials, like and unlike terms are discussed.

When terms have the same algebraic factors, they are like terms.

When terms have different algebraic factors, they are unlike terms.

Explanation:

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Measures the power output of the machine
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Read 2 more answers
Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an
Lera25 [3.4K]

Answer:

\dot Q_{out} = 13369.104\,kW

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0

The rate of heat transfer between the turbine and its surroundings is:

\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}

The specific enthalpies at inlet and outlet are, respectively:

h_{in} = 3076.41\,\frac{kJ}{kg}

h_{out} = 2675.0\,\frac{kJ}{kg}

The required output is:

\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW\dot Q_{out} = 13369.104\,kW

4 0
3 years ago
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