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grigory [225]
3 years ago
14

A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2

5 mm. Pressure difference across the area reduction is - 40 kN/m2 Determine the downstream velocity and the volume flow rate if the flow is ideal. i. Determine the downstream velocity if the flow is not ideal and has a velocity coefficient of Cy = 0.89.
Engineering
1 answer:
NISA [10]3 years ago
6 0

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

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Soloha48 [4]

Answer:

radius = 0.045 m

Explanation:

Given data:

density of oil = 780 kg/m^3

velocity = 20 m/s

height = 25 m

Total energy is = 57.5 kW

we have now

E = kinetic energy+ potential energy +  flow work

E = \dot m ( \frac{v^2}{2] +  zg + p\nu)

E = \dot m( \frac{v^2}{2] +  zg + p_{atm} \frac{1}{\rho})

57.5 \times 10^3 = \dot m ( \frac{20^2}{2} + 25 \times 9.81 + 101325 \frac{1}{780})

solving for flow rate

\dot m = 99.977we know that [tex]\dot m  = \rho AV

\dot m  = 780 \frac{\pi}{4} D^2\times 16

solving for d

99.97 = 780 \times \frac{\pi}{4} D^2\times 16

d = 0.090 m

so radius = 0.045 m

3 0
3 years ago
The product life cycle defines the stages that new products move through as they enter, are established in, and ultimately leave
Bas_tet [7]

Answer:

The four marketing mix of every new business are:

1. Product

2. Place

3. Price

4. Promotion

For each of the stages of product life cycle, those 4p should be use appropriately.

Explanation:

The four marketing mix of every new business are:

1. Product

2. Place

3. Price

4. Promotion

the product life cycle are directly proportional to the 4p of marketing. the product life cycle stages are introduction, growth, maturity and decline.

For each of the stages of product life cycle, those 4p should be use appropriately.

Stages of product life cycle and how the 4p fit into it.

The introduction stage:

at this stage, a new product just want to be introduced to the consumers. the product stage has being developed. The place where the product will fit in will also be consider. the location of people who consume this product. Pricing strategy consider a low price at the introduction stage, the business owner may not get any profit at this stage. then, continuous advertisement to create awareness of the product to the environment.

The growth stage:

the product will continuing to be move to different locations. the standard of the product quality will be maintained. the Pricing will start increasing. then, continuous advertisement to create awareness of the product and working on improving the product to suit the consumer.

the Mature stage:

At this stage, the consumer are fully aware of the product. wide range of location are reach. the pricing has reach its peak. Profit have been maximized. And, competitors of the product are in the market. Corporate social responsibility (CSR) will be the promotional value at this stage.

The Declining stage:

The business product have fully grown to its peak, and its only constant promotional values like CSR, advertisement, bonuses, can sustain it in the market. At this stage also, price comparison with other competitor should be carefully look into.

4 0
3 years ago
The weatherman states that the current temperature is 95 F and the dew point is 74 F. What is the current relative humidity?
spayn [35]

Answer:

Current Relative Humidity is 29.623

Given:

Current Temperature, T_{c} = 95 F = 35^{\circ}C

Dew point temperature, T_{d} = 74 F = 23.34^{\circ}C

Solution:

Now, in order to calculate the Relative Humidity, RH, we use the given formula:

T_{d} =100( \frac{\frac{aT_{c}}{b + T}b + lnRH}{a - \frac{aT_{c}}{b + T} + lnRH})

where

a = 17.625

b = 237.7

Now, using the above formula and given values:

23.34 = (237.7\frac{\frac{17.625\times 35}{ 237.7 + 35} + lnRH}{17.625 - \frac{17.625\times 35}{237.7 + 35} + lnRH})

23.34(17.625 - 2.26 + lnRH) = (237.7\times 2.26 + lnRH)

358.62 + 23.34lnRH) = (537.20 + lnRH)

358.62 + 23.34lnRH) = (537.20 + lnRH)

On solving the above eqn, we get:

RH = 29.623

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