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givi [52]
3 years ago
10

The engine of a 1500-kg automobile has a power rat- ing of 75 kW. Determine the time required to accelerate this car from rest t

o a speed of 100 km/h at full power on a level road. Is your answer realistic
Engineering
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

7.72 seconds

The answer is not realistic as the time is very less to reach to a speed of 100 km/hr

also, we have not taken other factors into consideration like wind drag etc.

Explanation:

Data provided in the question:

Mass of the engine = 1500 kg

Power rating = 75 kW = 75,000 W

Initial speed, v₁ = 0

Final speed = 100 km/hr = 100\times\frac{5}{18} = 27.78 m/s

Now,

Power = Work done ÷ Time

also,

Work done = Final energy - Initial energy

= \frac{1}{2}mv_2^2-\frac{1}{2}mv_1^2

= \frac{1}{2}\times1500\times27.78^2-\frac{1}{2}\times1500\times0^2

= 578703.70 J

thus,

75,000 = 578703.70 ÷ time

or

time = 7.716 s ≈ 7.72 seconds

The answer is not realistic as the time is very less to reach to a speed of 100 km/hr

also, we have not taken other factors into consideration like wind drag etc.

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Answer:

Below see details

Explanation:

A) It is attached. Please see the picture

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3 years ago
Line.
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Air supplied to a pneumatic system is supplied through the C. Actuator

Explanation

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7 0
4 years ago
After replacing a vacuum booster, the brakes lock up on a road test. Technician A says there is air trapped inside the brake lin
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Answer:

Technician B

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The brakes can lockup due to the following reasons

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A flat plate 1.5 m long and 1.0 m wide is towed in water at 20 o C in the direction of its length at a speed of 15 cm/s. Determi
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Answer:

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L = 1.5

B = 1.0

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Temperature = 20⁰C

At 20⁰C

Specific weight = 9790

Kinematic viscosity v = 1.00x10^-4m²/s

Dynamic viscosity u = 1.00x10^-3

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S = 5

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= 0.0158

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= 0.0944N

3 0
3 years ago
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