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azamat
3 years ago
7

A rectangular channel 6 m wide with a depth of flow of 3m has a mean velocity of 1.5 m/sec. The channel undergoes a smooth, grad

ual contraction to a width of 4.5 m. (a) Calculate the depth and velocity in the contracted section (Hint: y2 is between 2.6~2.9m). (b) Calculate the net fluid force on the walls and floor of the contraction in the flow direction. In each case, identify any assumptions that you made.

Engineering
1 answer:
k0ka [10]3 years ago
3 0

Answer:

The answer for (1) 2.07 m/s (2) F= 63.8kN

Explanation:

Solution

By applying the energy equation from the approach  section 1 to the contacted section 2 with negligible head losses and assuming a horizontal bottom

we have y₁ + V₁²/ 2g = y₂ +  q₂²/2gy₂²

Where

q is =flow rate

y = the depth

g = the acceleration

Kindly find an attached copy of the final solution for this question.

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denis23 [38]

Answer:

a)  T_m=1.787min

b)  MRR=35259.7mm^3/min

Explanation:

From the question we are told that:

Cast-iron block Dimension:

Lengthl=0.7m=>700mm

Width w=30mm

FeedF=0.25mm/tooth

Depth dp=3mm

Diameter d=75mm

Number of cutting teeth n=8

Rotation speed N=200rpm

Generally the equation for Approach is mathematically given by

x=\sqrt{Dd-d^2}

X=\sqrt{75*3-3^2}

X=14.69mm

Therefore

Effective length is given as

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L_e=700+14.69

L_e=714.69mm

a)

Generally the equation for Machine Time is mathematically given by

T_m=\frac{L_e}{F_m}

Where

F_m=F*n*N

F_m=0.25*8*200

F_m=400

Therefore

T_m=\frac{714.69}{400}

T_m=1.787min

b)

Generally the equation for Material Removal Rate. is mathematically given by

MRR=\frac{L*B*d}{t_m}

MRR=\frac{700*30*3}{1.787}

MRR=35259.7mm^3/min

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ANSWER QUICK<br>Why did Winston Churchill take over for Neville Chamberlain shortly after ww2? ​
kenny6666 [7]

Answer:neville chamberlain died

Explanation:

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3 years ago
Shortly after the introduction of a new​ coin, newspapers published articles claiming the coin is biased. The stories were based
garik1379 [7]

Answer:

(a) 0.12924

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Explanation:

(a)

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Variance = np(1 - p) = 100(1-0.5)=100*0.5=50

Standard deviation, s = \sqrt {variance}=\sqrt {50}= 7.071068

Z value for 108, z =\frac {108-100}{7.071068}= 1.131371

P( x ≥108) = P( z >1.13)= 0.12924

(b)

Taking into consideration significance level of 0.05 yet the value of p is greater than 0.05, it suggests that the coin is fair hence the coin can be used at the beginning of any sport event.

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Answer:

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A disk of radius 2.1 cm has a surface charge density of 5.6 µC/m2 on its upper face. What is the magnitude of the electric field
Assoli18 [71]

Answer:

=6.3*10^3 N/C

Explanation:

solution:

from this below equation (1)

E=σ/2εo(1-\frac{z}{\sqrt{z^2-R^2} } )...........(1)

we obtain:

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=6.3*10^3 N/C

8 0
3 years ago
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