Answer:
The answer for (1) 2.07 m/s (2) F= 63.8kN
Explanation:
Solution
By applying the energy equation from the approach section 1 to the contacted section 2 with negligible head losses and assuming a horizontal bottom
we have y₁ + V₁²/ 2g = y₂ + q₂²/2gy₂²
Where
q is =flow rate
y = the depth
g = the acceleration
Kindly find an attached copy of the final solution for this question.
Answer:
Output of plant=207.18 MW
Explanation:
Given input energy Q=450 MW
Brayton cycle efficiency%
Rankine cycle efficiency %
Combined efficiency for two cycle given as follow
We know that efficiency
out put of plant=
So output of plant=207.18 MW
Answer:
See attachment for step by step procedure into getting answer.
Explanation:
Given that;
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College Engineering 5+3 pts
4-6. A vertical cylindrical storage vessel is 10 m high and 2 m in diameter. The vessel contains liquid cyclohexane currently at a liquid level of 8 m. The vessel is vented to the atmosphere. A 1-cm-diameter hole develops in the bottom of the vessel. Calculate and plot the discharge rate of cyclohexane as a function of time until the vessel is completely empty. Show that the time to empty is the same as the time calculated using Equation 4-21.
See attachment for completed steps.
Answer:
<em>181 °C</em>
<em></em>
Explanation:
Initial pressure = 100 kPa
Initial temperature = 30 °C = 30 + 273 K = 303 K
Final pressure = 1200 kPa
Final temperature = ?
n = 1.2
For a polytropic process, we use the relationship
(/
) = (
/
)^γ
where γ = (n-1)/n
γ = (1.2-1)/1.2 = 0.1667
substituting into the equation, we have
(/303) = (1200/100)^0.1667
/303 = 12^0.1667
/303 = 1.513
= 300 x 1.513 = 453.9 K
==> 453.9 - 273 = 180.9 ≅ <em>181 °C</em>