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azamat
3 years ago
7

A rectangular channel 6 m wide with a depth of flow of 3m has a mean velocity of 1.5 m/sec. The channel undergoes a smooth, grad

ual contraction to a width of 4.5 m. (a) Calculate the depth and velocity in the contracted section (Hint: y2 is between 2.6~2.9m). (b) Calculate the net fluid force on the walls and floor of the contraction in the flow direction. In each case, identify any assumptions that you made.

Engineering
1 answer:
k0ka [10]3 years ago
3 0

Answer:

The answer for (1) 2.07 m/s (2) F= 63.8kN

Explanation:

Solution

By applying the energy equation from the approach  section 1 to the contacted section 2 with negligible head losses and assuming a horizontal bottom

we have y₁ + V₁²/ 2g = y₂ +  q₂²/2gy₂²

Where

q is =flow rate

y = the depth

g = the acceleration

Kindly find an attached copy of the final solution for this question.

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Explanation:

Given that

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Lets take heat transfer is Q ,then entropy change can be written as

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Now by putting the values

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The heat transfer ,Q= 8120 KJ

From first law of thermodynamics

Q = ΔU + W

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