Answer:
y = -1/10x^2 +2.5
Step-by-step explanation:
The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:
-1 -4 = -5
So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).
The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...
y = (1/(4p))(x -h) +k
y = -1/10x^2 +2.5
_____
You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.
Greetings!
"<span>Heather measured a swimming pool and made a scale drawing. In real life, the pool is 45 meters long. It is 65 millimeters long in the drawing. What scale did Heather use for the drawing?"...
65mm=</span>45m<span>
Reduce to Simpliest Form.
</span>65/5=<span>45/5
13mm=9m
As a Representative Fraction (scale), it would look like: (in regards to mm)
13:9000
Hope this helps.
-Benjamin</span>
Answer:
542 minutes
Step-by-step explanation:
currently our mean is =530
i got that by adding all the number out which equal too =2,650
and divide it by how many number there are which is 5
2,650/5=530
After some trial and error i found it
so you add 494+690+502+478+486+542=3,192
3,192/6=532
and that was our goal
so the 6th month she talked on the phone for 542 minutes
pls mark me brainliest
The two numbers are 14 and 15.
Answer:
is an odd function.
Step-by-step explanation:
We are asked to prove whether
is even or odd.
We know that a function
is even if
and a function
is odd, when
.
We also know that an even function is symmetric with respect to y-axis and an odd function is symmetric about the origin.
Upon looking at our attachment, we can see that
is symmetric with respect to origin, therefore,
is an odd function.