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spin [16.1K]
3 years ago
8

The use of seat belts in cars has significantly reduced the number of crash fatalities. Which statement best explains how the ma

rket forces of supply and demand guided the development of seat-belt technology?
A.When a large enough supply of seat-belt parts became available, the public demand for their use in cars increased.B.Consumers' desire for more comfortable seat belts led engineers to improve seat belts.C.Engineers recognized the dangers of not wearing a seat belt and decided to develop systems that would be affordable to manufacture.D.As car manufacturers developed seat-belt technology, they began to advertise seat belts' ability to prevent injuries and death to consumers.
Engineering
2 answers:
julsineya [31]3 years ago
5 0

Consumers desire for more comfortable seat belts led engineers to improve seat belts.

Explanation:

dimaraw [331]3 years ago
5 0

Answer:

B. Consumers' desire for more comfortable seat belts led engineers to improve seat belts.

Explanation:

just got the question right on APEX

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A manometer connected to a Pitot-static tube has a difference in the height of the two columns of water of 10 cm when the Pitot-
kaheart [24]

Answer:

v = 40 m/s

Explanation:

Difference in the height of the two columns:

h_m = \triangle h = 10 cm \\h_m = 0.1 m

Air density, \rho_{air} = 1.225 kg/m^3

Water density, \rho_{w} = 1000 kg/m^3

The velocity of air flow is given by the equation:

v =  \sqrt{2gh_m (\frac{p_w}{p_{air}} - 1) } \\\\v =  \sqrt{2*9.81*0.1 (\frac{1000}{1.225} - 1) }\\\\v = 40 m/s

7 0
4 years ago
A wastewater is to be disinfected using ultraviolet (UV) light. Batch experiments find that the bacterial concentration decays u
Ksivusya [100]

Answer:

k = 0.1118 per min

Explanation:

Assume;

Initial number of bacteria = N0

Number of bacteria IN 'T' time = Nt

So,

Nt=N0e^{-kt}\\\\in\ 6.2 min\\\\\\frac{N0}{2}= N0e^{-k(6.2)}\\\\ln\frac{1}{2} = -k[6.2]

k = 0.1118 per min

7 0
3 years ago
The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change i
ehidna [41]

Answer:

Change in length = 0.1257 mm

Change in diameter= -0.03771mm

Explanation:

Given

Diameter, d = 15 mm

Length of rod, L = 200mm

F = Force= 300N

d = 0.015m

Ep=2.70 GPa, np=0.4.

First, we have to calculate the normal stress using

σ = F/A where F = Force acting on the Cross-sectional area

A = Area

Area is calculated as πd²/4 where d = 0.015m

A = 22/7 * 0.015²/4

A = 0.000176785714285m²

A = 1.768E-4m²

So, stress. σ = 300N/1.768E-4m²

σ = 1696832.579185520Pa

σ = 1.697MPa

Calculating E(long)

E(long) = σ /Ep

E(long) = 1.697E-3/2.70

E(long) = 0.0006285

At this point, we fan now calculate the change in length of the element;

∆L = E(long) * L

∆L = 0.0006285 * 200mm

∆L = 0.1257mm

Calculating E(lat)

E(lat) = -np * E(long)

E(lat) = -4 * 0.0006285

E(lat) = -0.002514

At this point, we can now calculate the change in diameter of the element;

∆D = E(lat) * D

∆L = -0.002514 * 15mm

∆L = -0.03771mm

8 0
3 years ago
How much power do a capacitor and inductor dissipate? Assume the capacitor/inductor have no parasitic resistance (no resistor in
Mariana [72]
They do in fact heat up while receiving energy.
4 0
3 years ago
A) Gravity attracts horizontally downwards the weight of any object such a building or a part of building. (True / False)
PtichkaEL [24]

Answer:

  1. True
  2. True
  3. False
  4. True

Explanation:

  • True
  • True
  • False
  • True

3 0
3 years ago
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