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alekssr [168]
1 year ago
12

what typical size are the metal studs to be for interior walls unless noted differently on the drawings? what spacing is to be u

sed?
Engineering
1 answer:
Angelina_Jolie [31]1 year ago
7 0

Sizes of metal studs vary, but 2-1/2″ is the most common. Spacing is typically 16″ or 24″ center-to-center.

<h3>What is metal studs ?</h3>

           Metal studs are commonly used to support load-bearing as well as non-load-bearing walls. Such walls are common in home decoration and have a light gauge metal frame. This material is commonly used when erecting temporary partitions or structures.

            Wood was the only option for building applications long before the use of metal studs. Wood is capable of providing substantial support to a variety of structures. Because homebuilders and contractors had no choice but to use wood, it became the standard option for studs.

     Because metal stud framing is unfamiliar to traditional or small builders, wood studs are used. The transition from wood to metal, on the other hand, is very simple. If you choose to use metal studs, it is critical to work with a building and frame crew that has previously erected metal stud construction rather than a traditional wood framing crew.

             While some modern construction professionals tout the advantages of wooden studs over metal counterparts, there are numerous advantages to using metal studs. As a result, they are in high demand in the market.

To learn more about metal studs refer :

brainly.com/question/27865038

#SPJ4

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vlabodo [156]

Answer:

C

Explanation:

5 0
3 years ago
A satellite orbits the Earth every 2 hours at an average distance from the Earth's centre of 8000km. (i) What is the average ang
AlexFokin [52]

Answer:

i)ω=3600 rad/s

ii)V=7059.44 m/s

iii)F=1245.8 N

Explanation:

i)

We know that angular speed given as

\omega =\dfrac{d\theta}{dt}

We know that for one revolution

θ=2π

Given that time t= 2 hr

So

ω=θ/t

ω=2π/2 = π rad/hr

ω=3600 rad/s

ii)

Average speed V

V=\sqrt{\dfrac{GM}{R}}

Where M is the mass of earth.

R is the distance

G is the constant.

Now by putting the values

V=\sqrt{\dfrac{GM}{R}}

V=\sqrt{\dfrac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{8000\times 10^3}}

V=7059.44 m/s

iii)

We know that centripetal fore given as

F=\dfrac{mV^2}{R}

Here given that m= 200 kg

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so now by putting the values

F=\dfrac{mV^2}{R}

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3 0
3 years ago
You have just finished your OST takeoffs for a single-story home and found 175 LF of interior walls with 2x6 studs 14" OC. The h
zimovet [89]

Answer:

Total BF for the interior wall is 7.50BD

Explanation:

Given Data:

· Size of stud = 2” x 6”

· Height of Wall = 8 ft

· Top plates = 2

· Bottom Plate = 1

BF stands for board feet in lumber/wood terminology. It is the unit of volume.

1 BF (Board feet) = 1 ft x 1 ft x 1 inch

Since there are total three plates at top and bottom, we have to deduct their thickness from wall height to calculate height of stud.

Height of stud = 8’ – 3 x 2” = 7’6” = 7.5 ft

Board feet of one stud = 7.50 6/12 x 2 = 7.50 BD

Total BF for the interior wall is 7.50BD

7 0
3 years ago
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shutvik [7]

Answer:

Overall project duration

Explanation:

Scheduling can best be defined as the process used to determine a overall project duration.

8 0
3 years ago
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