Answer: It helps your back posture and shows respect
Explanation:
Answer:
The amount of cargo the plane can carry is 8707.89 N
Explanation:
The surface area of the wings facing the air = 30×6×2 × sin(2.5) = 15.7 m²
The speed of the plane 550 km/h = 152.78 m/s
The volume of air cut through per second = 15.7 × 152.78 = 2399.07 m³
The mass of air = Volume × Density = 2399.07 × 0.37 = 887.65 kg
Weight of air = Mass × Acceleration due to gravity = 887.65 × 9.81 = 8707.89 N
Given that the plane is already airborne, the additional cargo the plane can carry is given by the available lift force of the plane.
The amount of cargo the plane can carry = 8707.89 N
If the diameter of the bar is 0.490 at this load, determine I. the engineering stress and strain, and [2] II. the true stress and strain is 1561. 84 MPa.
<h3>What is strain?</h3>
Strain is a unitless degree of ways a great deal an item receives larger or smaller from an implemented load. Normal stress happens while the elongation of an item is in reaction to an everyday pressure (i.e. perpendicular to a surface), and is denoted via way of means of the Greek letter epsilon.
- L = 20 cm d x 1 = 0.21 cm
- dx 2 = 0.25 cmF=5500 a) σ= F/A1= 5000/(π/4x(0.0025)^2)= 1018.5916 MPa lateral stress= Ad/d1= (0.0021-0.0025)/0.0025 = - 0.1 longitudinal stress (ɛ_l)= -lateral stress/v = -(-0.16)/0.3
- (assuming a poisson's ration of 0.3) ε_l=0.16/0.3 = 0.5333
- b) σ_true= σ(1+ ɛ_I)= 1018.5916(1+0.5333
- = 1561.84 MPa.
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