(1-tanx)(1-cotx)=2-secxcscx
1 - tanx - cotx + 1 = 2 - secxcscx
2 - tanx - cotx = 2 - 1/(sinxcosx)
tanx + cotx = 1/(sinxcosx)
sin^2(x) + cos^2(x) = 1
Answer:
5√3 miles per hour
Step-by-step explanation:
Throughout their journey, the component of velocity of rowboat B to the east is the same as that of rowboat A:
(10 mph)(cos(π/3)) = 5 mph
Meanwhile, the component of velocity of rowboat B to the north is ...
(10 mph)(sin(π/3)) = 5√3 mph
Since rowboat A is always traveling in a direction that is at right angles to the direction between the boats, it contributes nothing to their relative speed. Since rowboat B is always directly north of rowboat A, its speed to the north is their relative speed.
The distance between the rowboats is increasing at 5√3 mph ≈ 8.66 mph.
If a student receives a score of 80, how many questions did this student answer ... (5). Let x = the first number, and y = the second number ... If John only has 25 coins in his pocket, how many of the coins are quarters?
80/5=16
16*3=48
80-48=32
32\5=6.4
She spends $6.40 each day