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GREYUIT [131]
3 years ago
9

What the valie of 8+(27÷9)2?

Mathematics
2 answers:
Dafna11 [192]3 years ago
7 0
First you do 27 divided by 9 which is 3
Then you multiply that by 2 which is 6
Then add 8
Final answer is 14
kirill115 [55]3 years ago
6 0

Answer:

14

Explanation:

Parenthesis, Exponents, Multiply, Divide, Add, Subtract

27 ÷ 9 = 3

3 · 2 = 6

8 + 6 = 14

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Trisha has a game board as shown below, which is a square that has a total area of 400 square inches. The area of the large circ
Mazyrski [523]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

Total area of square inches = 400

The area of the large circle = 314

Now, we need to find the probability that Trisha will not get any points with one randomly thrown dart that lands somewhere inside the square,

Let E be the event the Trisha will get points .

so,

P(E)=\frac{314}{400}

As we know that

P(E')=1-P(E)\\\\P(E')=1-\frac{314}{400}\\\\P(E')=\frac{400-314}{400}\\\\P(E')=\frac{86}{400}\\\\P(E')=0.215=0.22

So, Probability that Trisha will not get any points with one randomly thrown dart that lands somewhere inside the square = 0.22

So, First option is correct.

4 0
3 years ago
Read 2 more answers
Solve by elimination 5x+y=0 5x+2y=30
xxMikexx [17]
I think the answer is (-6,30) unless I messed up somewhere
5 0
3 years ago
10 points if you solve this one problem.
zalisa [80]

Answer:

150

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

<1 + <2 = <3

3x+11 + 3x+19 = 7x+10

Combine like terms

6x+30 = 7x+10

Subtract 6x from each side

6x -6x+30 = 7x-6x+10

30 = x+10

Subtract 10 from each side

30-10 = x+10-10

20 =x

We need to find angle 3

<3 = 7x+10

    = 7(20)+10

    = 140+10

    = 150

7 0
3 years ago
Please hurry
Leya [2.2K]
The second answer i think is the best one
3 0
3 years ago
Read 2 more answers
Anybody Know This. ?
frosja888 [35]

Answer:

The answer is the third option from the top:

0, 0, 11, 15, 26, 32, 45, 46, 46, 46, 60, 71, 84, 88

4 0
3 years ago
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