Question is: how many 84s will fit in 5376? Let's think about some easy multiples:
84 * 100 = 8400, so it's too big
84 * 10 = 840, so it might work
84 | 5376 | 10
-840
84 | 4536 | 10
-840
84 | 3696 | 10
-840
84 | 2856 | 10
-840
84 | 2016 | 10
-840
84 | 1176 | 10
-840
84 | 336
We can't fit any more 840 in 336, so we check how many 84s are in 336 and what's the remainder:
84 | 336 | 4
- 336
So there's no remainder. Now we add all the partial quotients to get the final result:
10 + 10 + 10 + 10 + 10 + 10 + 4 = <u>64
</u>It's correct, I checked it with calculator. I just hope you'll be able to read something from that, it's quite difficult to do partial dividing with no pencil and paper :)
I just took the test the answer is 9 cm.
Answer:
(2, -5)
Step-by-step explanation:
x is defined by the first equation as x = -3y – 13. Substitute -3y – 13 for x in the second equation:
2( -3y – 13) + 2y = -6.
Performing the indicated multiplication, we get:
-6y - 26 + 2y = -6
Combining like terms results in:
-4y = 20, so that y = -5
Using the first equation, we find x for y = -5:
x = -3(-5) - 13 = 2
The solution is thus (2, -5) (Answer C)
Let x be the number of mm of pure alcohol to be added:
I will add the mm to express the volume in mm
100mm.(19%) + (100%).x mL = (100 mL+x mL).(40%).
Now right again without the %
100.(0.19) + x.(1) = (100+x).(0.4)
19 + x = = 40 + 04x
x - 0.4x = 40 - 19
0.6 x = 21
x = 21/0.6 and x = 35 mL. This te quantity of pure alcohol should to be added to get a solution at 40%.
Remove the negative sign usually. Hope this helps!
