2 years ago

Factorize:a)x³-3x²+2x-6-xy+3yb)mn-mx-n+x

2 answers:

7 0

$\displaystyle \Large \boldsymbol{} a) \ \underline{x^2-3x}+\underline{2x-6}-\underline{xy+3y}=\\\\\\x(x-3)+2(x-3)-y(x-3)=\boxed{(x-3)(x-y+2)} \\\\\\b) \ mn-mx-n+x=m(n-x)-(n-x) =\boxed{ (m-1)(n-x)}$

DaniilM [7]2 years ago

3 0

Part b answer is this

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Factorize:a)x³-3x²+2x-6-xy+3yb)mn-mx-n+x​

Factorize:a)x³-3x²+2x-6-xy+3yb)mn-mx-n+x