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3 years ago

Factorize:a)x³-3x²+2x-6-xy+3yb)mn-mx-n+x

2 answers:

7 0

$\displaystyle \Large \boldsymbol{} a) \ \underline{x^2-3x}+\underline{2x-6}-\underline{xy+3y}=\\\\\\x(x-3)+2(x-3)-y(x-3)=\boxed{(x-3)(x-y+2)} \\\\\\b) \ mn-mx-n+x=m(n-x)-(n-x) =\boxed{ (m-1)(n-x)}$

DaniilM [7]3 years ago

3 0

Part b answer is this

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Solve systems of equations by algebraically x-2y=7 2x+5y =5

Natali [406]

Answer:

(5,-1) or x=5 y=-1

Step-by-step explanation:

I used the substitution method to solve this!

1. Pick one of your equations and solve for one of the variables. I chose the first equation and solved for x.

x-2y=7

(Move the -2y to the other side of the equation in order to get the x by itself. You do the opposite, so it becomes +2y.)

x=2y+7

2. Now take your second equation and plug in what you got for x into the x variable.

2(2y+7)+5y=5

(Multiple 2 by everything inside of the parentheses.)

4y+14+5y=5

(We want to get the y by itself, so move the 14 to the other side.)

4y+5y=-14+5

(Combine all the like terms.)

9y=-9

(Divide the 9 from the y. What you do to one side you must do to the other.)

y=-1

3. Since you have one variable solved for. Now take the first equation and plug in your y.

x-2(-1)=7

(Multiple -2 by -1)

x+2=7

(Move the 2 to the other side in order to get the x by itself.)

x=5

4. If needed, plug in your x and y values into the equations in order to check your answer.

Hope this could help!

8 0

3 years ago

Read 2 more answers

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

5 0

3 years ago

Rewrite 7 − 8 using the additive inverse

DedPeter [7]

Answer:

-8 + 7

Step-by-step explanation:

7 - 8 = -1

-8 + 7 = -1

7 0

4 years ago

Is (-4,4) the solution of the system. 4x+5y>-6 and -2x+7y>20

nikklg [1K]

Answer:

It is a solution, one of an infinite number of solutions.

Step-by-step explanation:

You can check to see if the given point is in the solution set:

4(-4) +5(4) = -16 +20 = 4 > -6 . . . . yes

-2(-4) +7(4) = 8 +28 = 36 > 20 . . . yes

The offered point satisfies both inequalities, so is in the solution set. It is not the solution, but is one of an infinite number of solutions.

7 0

3 years ago

All of the following fractions are proper fractions, except

eduard

Answer:

1/2

Step-by-step explanation:

8 0

3 years ago

Factorize:a)x³-3x²+2x-6-xy+3yb)mn-mx-n+x​

Factorize:a)x³-3x²+2x-6-xy+3yb)mn-mx-n+x